POJ 3094 Quicksum 水题

题意：A = 1， B = 2， C = 3， ····  Z = 26, ' ' = 0. 例如：

ACM: 1*1 + 2*3 + 3*13 = 46

MID CENTRAL: 1*13 + 2*9 + 3*4 + 4*0 + 5*3 + 6*5 + 7*14 + 8*20 + 9*18 + 10*1 + 11*12 = 650

题解：

#include <iostream>
using namespace std;

int main()
{
char str[256];
while ( cin.getline(str,256,'\n') )
{
if ( str[0] == '#' ) break;
long sum = 0;
long len = strlen(str);
for ( int i = 0; i < len; i++ )
{
if ( str[i] == ' ' ) continue;
sum += ( str[i] - 'A' + 1 ) * ( i + 1 );
}
cout << sum << endl;
}
return 0;
}