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2011-08-29 09:00 302 查看




1863: Above Average

ResultTIME LimitMEMORY LimitRun TimesAC TimesJUDGE

3s8192K1081602Standard
It is said that 90% of frosh expect to be above average in their class. You are to provide a reality check.
The first line of standard input contains an integer C, the number of test cases. C data sets follow. Each data set begins with an integer, N, the number of people in the class (1 <= N <= 1000). N integers follow, separated by spaces or newlines, each giving
the final grade (an integer between 0 and 100) of a student in the class. For each case you are to output a line giving the percentage of students whose grade is above average, rounded to 3 decimal places.

Sample Input

5
5 50 50 70 80 100
7 100 95 90 80 70 60 50
3 70 90 80
3 70 90 81
9 100 99 98 97 96 95 94 93 91

Output for Sample Input

40.000%
57.143%
33.333%
66.667%
55.556%


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Problem Set with Online Judge System Version 3.12

Jilin University

Developed by skywind,
SIYEE

#include<cstdio>

int average(int p[],int n)

{

int sum=0;

for(int i=0;i<n;i++)sum+=p[i];

return sum/n;

}

int main()

{

int n;

int m;

int a[10000];

scanf("%d",&n);

for(int i=0;i<n;i++)

{

scanf("%d",&m);

for(int j=0;j<m;j++)

{

scanf("%d",&a[j]);

}

int ave=average(a,m);

int count=0;

for(int j=0;j<m;j++)

{

if(a[j]>ave)++count;

}

printf("%.3f",100*(float)count/m);

printf("%c\n",'%');

}

return 0;

}
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