Chapter 03 - Joins - Solutions

---------------------------------------------------------------------

-- Microsoft SQL Server 2008 T-SQL Fundamentals

-- Chapter 3 - Joins

-- Solutions

-- ?2008 Itzik Ben-Gan

---------------------------------------------------------------------

-- 1

-- 1-1

-- Run the following code to create the Nums auxiliary table

-- in the TSQLFundamentals2008 database:

-- Auxiliary table of nums

SET NOCOUNT ON;

USE TSQLFundamentals2008;

IF OBJECT_ID('dbo.Nums', 'U') IS NOT NULL DROP TABLE dbo.Nums;

CREATE TABLE dbo.Nums(n INT NOT NULL PRIMARY KEY);

DECLARE @i AS INT = 1;

BEGIN TRAN

WHILE @i <= 100000

BEGIN

INSERT INTO dbo.Nums VALUES(@i);

SET @i = @i + 1;

END

COMMIT TRAN

SET NOCOUNT OFF;

GO

-- 1-2

-- Write a query that generates 5 copies out of each employee row

-- Tables involved: TSQLFundamentals2008 database, Employees and Nums tables

--Desired output

empid firstname lastname n

----------- ---------- -------------------- -----------

1 Sara Davis 1

2 Don Funk 1

3 Judy Lew 1

4 Yael Peled 1

5 Sven Buck 1

6 Paul Suurs 1

7 Russell King 1

8 Maria Cameron 1

9 Zoya Dolgopyatova 1

1 Sara Davis 2

2 Don Funk 2

3 Judy Lew 2

4 Yael Peled 2

5 Sven Buck 2

6 Paul Suurs 2

7 Russell King 2

8 Maria Cameron 2

9 Zoya Dolgopyatova 2

1 Sara Davis 3

2 Don Funk 3

3 Judy Lew 3

4 Yael Peled 3

5 Sven Buck 3

6 Paul Suurs 3

7 Russell King 3

8 Maria Cameron 3

9 Zoya Dolgopyatova 3

1 Sara Davis 4

2 Don Funk 4

3 Judy Lew 4

4 Yael Peled 4

5 Sven Buck 4

6 Paul Suurs 4

7 Russell King 4

8 Maria Cameron 4

9 Zoya Dolgopyatova 4

1 Sara Davis 5

2 Don Funk 5

3 Judy Lew 5

4 Yael Peled 5

5 Sven Buck 5

6 Paul Suurs 5

7 Russell King 5

8 Maria Cameron 5

9 Zoya Dolgopyatova 5

(45 row(s) affected)

-- Solution

SELECT E.empid, E.firstname, E.lastname, Nums.n

FROM HR.Employees AS E

CROSS JOIN dbo.Nums

WHERE Nums.n <= 5

ORDER BY n, empid;

-- 1-3

-- c. (Advanced, Optional)

-- Write a query that returns a row for each employee and day

-- in the range June 12, 2009 ?June 16 2009.

-- Tables involved: TSQLFundamentals2008 database, Employees and Nums tables

--Desired output

empid dt

----------- -----------------------

1 2009-06-12 00:00:00.000

1 2009-06-13 00:00:00.000

1 2009-06-14 00:00:00.000

1 2009-06-15 00:00:00.000

1 2009-06-16 00:00:00.000

2 2009-06-12 00:00:00.000

2 2009-06-13 00:00:00.000

2 2009-06-14 00:00:00.000

2 2009-06-15 00:00:00.000

2 2009-06-16 00:00:00.000

3 2009-06-12 00:00:00.000

3 2009-06-13 00:00:00.000

3 2009-06-14 00:00:00.000

3 2009-06-15 00:00:00.000

3 2009-06-16 00:00:00.000

4 2009-06-12 00:00:00.000

4 2009-06-13 00:00:00.000

4 2009-06-14 00:00:00.000

4 2009-06-15 00:00:00.000

4 2009-06-16 00:00:00.000

5 2009-06-12 00:00:00.000

5 2009-06-13 00:00:00.000

5 2009-06-14 00:00:00.000

5 2009-06-15 00:00:00.000

5 2009-06-16 00:00:00.000

6 2009-06-12 00:00:00.000

6 2009-06-13 00:00:00.000

6 2009-06-14 00:00:00.000

6 2009-06-15 00:00:00.000

6 2009-06-16 00:00:00.000

7 2009-06-12 00:00:00.000

7 2009-06-13 00:00:00.000

7 2009-06-14 00:00:00.000

7 2009-06-15 00:00:00.000

7 2009-06-16 00:00:00.000

8 2009-06-12 00:00:00.000

8 2009-06-13 00:00:00.000

8 2009-06-14 00:00:00.000

8 2009-06-15 00:00:00.000

8 2009-06-16 00:00:00.000

9 2009-06-12 00:00:00.000

9 2009-06-13 00:00:00.000

9 2009-06-14 00:00:00.000

9 2009-06-15 00:00:00.000

9 2009-06-16 00:00:00.000

(45 row(s) affected)

-- Solution

SELECT E.empid,

DATEADD(day, D.n - 1, '20090612') AS dt

FROM HR.Employees AS E

CROSS JOIN Nums AS D

WHERE D.n <= DATEDIFF(day, '20090612', '20090616') + 1

ORDER BY empid, dt;

-- 2

-- Return US customers, and for each customer the total number of orders

-- and total quantities.

-- Tables involved: TSQLFundamentals2008 database, Customers, Orders and OrderDetails tables

--Desired output

custid numorders totalqty

----------- ----------- -----------

32 11 345

36 5 122

43 2 20

45 4 181

48 8 134

55 10 603

65 18 1383

71 31 4958

75 9 327

77 4 46

78 3 59

82 3 89

89 14 1063

(13 row(s) affected)

-- Solution

SELECT C.custid, COUNT(DISTINCT O.orderid) AS numorders, SUM(OD.qty) AS totalqty

FROM Sales.Customers AS C

JOIN Sales.Orders AS O

ON O.custid = C.custid

JOIN Sales.OrderDetails AS OD

ON OD.orderid = O.orderid

WHERE C.country = N'USA'

GROUP BY C.custid;

-- 3

-- Return customers and their orders including customers who placed no orders

-- Tables involved: TSQLFundamentals2008 database, Customers and Orders tables

-- Desired output

custid companyname orderid orderdate

----------- --------------- ----------- ------------------------

85 Customer ENQZT 10248 2006-07-04 00:00:00.000

79 Customer FAPSM 10249 2006-07-05 00:00:00.000

34 Customer IBVRG 10250 2006-07-08 00:00:00.000

84 Customer NRCSK 10251 2006-07-08 00:00:00.000

...

73 Customer JMIKW 11074 2008-05-06 00:00:00.000

68 Customer CCKOT 11075 2008-05-06 00:00:00.000

9 Customer RTXGC 11076 2008-05-06 00:00:00.000

65 Customer NYUHS 11077 2008-05-06 00:00:00.000

22 Customer DTDMN NULL NULL

57 Customer WVAXS NULL NULL

(832 row(s) affected)

-- Solution

SELECT C.custid, C.companyname, O.orderid, O.orderdate

FROM Sales.Customers AS C

LEFT JOIN Sales.Orders AS O

ON O.custid = C.custid;

-- 4

-- Return customers who placed no orders

-- Tables involved: TSQLFundamentals2008 database, Customers and Orders tables

-- Desired output

custid companyname

----------- ---------------

22 Customer DTDMN

57 Customer WVAXS

(2 row(s) affected)

-- Solution

SELECT C.custid, C.companyname

FROM Sales.Customers AS C

LEFT JOIN Sales.Orders AS O

ON O.custid = C.custid

WHERE O.orderid IS NULL;

-- 5

-- Return customers with orders placed on Feb 12, 2007 along with their orders

-- Tables involved: TSQLFundamentals2008 database, Customers and Orders tables

-- Desired output

custid companyname orderid orderdate

----------- --------------- ----------- -----------------------

66 Customer LHANT 10443 2007-02-12 00:00:00.000

5 Customer HGVLZ 10444 2007-02-12 00:00:00.000

(2 row(s) affected)

-- Solution

SELECT C.custid, C.companyname, O.orderid, O.orderdate

FROM Sales.Customers AS C

JOIN Sales.Orders AS O

ON O.custid = C.custid

WHERE O.orderdate = '20070212';

-- 6 (Optional, Advanced)

-- Return customers with orders placed on Feb 12, 2007 along with their orders

-- Also return customers who didn't place orders on Feb 12, 2007

-- Tables involved: TSQLFundamentals2008 database, Customers and Orders tables

-- Desired output

custid companyname orderid orderdate

----------- --------------- ----------- -----------------------

72 Customer AHPOP NULL NULL

58 Customer AHXHT NULL NULL

25 Customer AZJED NULL NULL

18 Customer BSVAR NULL NULL

91 Customer CCFIZ NULL NULL

...

33 Customer FVXPQ NULL NULL

53 Customer GCJSG NULL NULL

39 Customer GLLAG NULL NULL

16 Customer GYBBY NULL NULL

4 Customer HFBZG NULL NULL

5 Customer HGVLZ 10444 2007-02-12 00:00:00.000

42 Customer IAIJK NULL NULL

34 Customer IBVRG NULL NULL

63 Customer IRRVL NULL NULL

73 Customer JMIKW NULL NULL

15 Customer JUWXK NULL NULL

...

21 Customer KIDPX NULL NULL

30 Customer KSLQF NULL NULL

55 Customer KZQZT NULL NULL

71 Customer LCOUJ NULL NULL

77 Customer LCYBZ NULL NULL

66 Customer LHANT 10443 2007-02-12 00:00:00.000

38 Customer LJUCA NULL NULL

59 Customer LOLJO NULL NULL

36 Customer LVJSO NULL NULL

64 Customer LWGMD NULL NULL

29 Customer MDLWA NULL NULL

...

(91 row(s) affected)

-- Solution

SELECT C.custid, C.companyname, O.orderid, O.orderdate

FROM Sales.Customers AS C

LEFT JOIN Sales.Orders AS O

ON O.custid = C.custid

AND O.orderdate = '20070212';

-- 7 (Optional, Advanced)

-- Return all customers, and for each return a Yes/No value

-- depending on whether the customer placed an order on Feb 12, 2007

-- Tables involved: TSQLFundamentals2008 database, Customers and Orders tables

-- Desired output

custid companyname HasOrderOn20070212

----------- --------------- ------------------

1 Customer NRZBB No

2 Customer MLTDN No

3 Customer KBUDE No

4 Customer HFBZG No

5 Customer HGVLZ Yes

6 Customer XHXJV No

7 Customer QXVLA No

8 Customer QUHWH No

9 Customer RTXGC No

10 Customer EEALV No

...

(91 row(s) affected)

-- Solution

SELECT DISTINCT C.custid, C.companyname,

CASE WHEN O.orderid IS NOT NULL THEN 'Yes' ELSE 'No' END AS [HasOrderOn20070212]

FROM Sales.Customers AS C

LEFT JOIN Sales.Orders AS O

ON O.custid = C.custid

AND O.orderdate = '20070212';