2011阿里巴巴程序设计公开赛 1003 I'll play a trick on you

#include <iostream>

using namespace std;
#define LEN 101
char num1[LEN];
char num2[LEN];
int a[LEN];
int b[LEN];
int result[LEN];

int main(){
int i,j;
int t;
cin>>t;
for(j=1;j<=t;j++){
scanf("%s%s",num1,num2);
int len1=strlen(num1);
int len2=strlen(num2);
int len=len1+len2;
int sum=0;
for(i=0;i<len1;i++){
a[i]=num1[i]-'0';
sum+=a[i];
}
for(i=0;i<len2;i++){
b[i]=num2[i];
sum+=b[i]-'0';
}
printf("Case %d: %d\n",j,sum);
}
return 0;
}