hdu 1165 Eddy's research II
2011-08-05 10:11
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/*Ackerman函数: 当m=1时: A(1,n) = A(0,A(1,n-1)) = A(1,n-1)+1 = A(0,A(1,n-2))+1 = A(1,n-2)+2..... = A(1,n-n)+n = A(0,1)+n=n+2; 当m=2时: A(2,n) = A(1,A(2,n-1)) = A(2,n-1)+2 = A(1,A(2,n-2))+2=A(2,n-2)+2*2... = A(2,n-n)+2*n = 2*n+3; 当m=3时: A(3,n) = A(2,A(3,n-1)) = 2*(A(3,n-1)+3; */ #include<iostream> using namespace std; long Ackermann(long m,long n) { if(n==0) return Ackermann(m-1,1); else if(m==2) return 2*n+3; else return 2*Ackermann(m,n-1)+3; } int main() { long n,m; while(scanf("%ld %ld",&m,&n)!=EOF) { if(m==1) { printf("%ld\n",n+2); } else if(m == 2) { printf("%ld\n",2*n+3); } else if(m == 3) { printf("%ld\n",Ackermann(m,n)); } } return 0; }
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