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用xml作参数一次插入多条数据

2011-06-20 15:17 363 查看
1.存储过程方法:

declare @customers xml
set @customers='<cus bpNo=''15'' MNo=''商户ID1'' MName=''商户名称1'' /><cus bpNo=''15'' MNo=''商户ID2'' MName=''商户名称2'' />'

INSERT control.tb_ExternalEnterprise(BPNo,EnterpriseId,EnterpriseName)
SELECT R.c.value('@bpNo','CHAR(6)'),R.c.value('@MNo','VARCHAR(50)'),
R.c.value('@MName','NVARCHAR(30)')
FROM @customers.nodes('cus') R(c)

2.sql语句方法:

INSERT tb_ExternalEnterprise(BPNo,EnterpriseId,EnterpriseName)
SELECT b.*
FROM (select cast('<cus bpNo=''15'' MNo=''商户ID1'' MName=''商户名称1''/>
<cus bpNo=''15'' MNo=''商户ID2'' MName=''商户名称2'' />' as xml) a)t
cross apply(select R.c.value('@bpNo','CHAR(6)') as bpNo,
R.c.value('@MNo','VARCHAR(50)') as MNo,
R.c.value('@MName','NVARCHAR(30)') as MName
from t.a.nodes('cus') R(c)) b

System.Text.StringBuilder sb = new System.Text.StringBuilder("'");
for (int i = 0; i < count; i++)
{
sb.AppendFormat("<cus bpNo='{0}' />", i.ToString());//Guid.NewGuid().ToString());
}
sb.Append("'");

************************* SqlBulkCopy ********************************

private static long SqlBulkCopyInsert()
{
Stopwatch stopwatch = new Stopwatch();
stopwatch.Start();

DataTable dataTable = GetTableSchema();
string passportKey;
for (int i = 0; i < count; i++)
{
passportKey = i.ToString();//Guid.NewGuid().ToString();
DataRow dataRow = dataTable.NewRow();
dataRow[0] = passportKey;
dataTable.Rows.Add(dataRow);
}

SqlBulkCopy sqlBulkCopy = new SqlBulkCopy(connectionString);
sqlBulkCopy.DestinationTableName = "Passport";
sqlBulkCopy.BatchSize = dataTable.Rows.Count;
SqlConnection sqlConnection = new SqlConnection(connectionString);
sqlConnection.Open();
if (dataTable != null && dataTable.Rows.Count != 0)
{
sqlBulkCopy.WriteToServer(dataTable);
}
sqlBulkCopy.Close();
sqlConnection.Close();

stopwatch.Stop();
return stopwatch.ElapsedMilliseconds;
}
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