gettimeofday
2011-05-20 16:00
387 查看
有些事看起来很简单,真的做好却需要费一番力气。
今天闲来无事,决定做个小程序,把刚写的程序中用到的gettimeofday函数取出的时间,转换成标准的时间格式(YYYY-MM-DD HH24:MI:SS.USEC),很快把程序做出来了。
#include <stdio.h>
#include <sys/time.h>
//typedef long long Int64;
#define BEIJINGTIME 8;
main()
{
struct timeval tv;
struct timezone tz;
long tm = 0;
long sec = 0, usec = 0;
int yy = 0, mm = 0, dd = 0, hh = 0, mi = 0, ss = 0, ms =0;
int m[12] = {31, 28, 31, 30, 31, 30, 31, 31, 30, 31, 30, 31};
int i;
gettimeofday(&tv, &tz);
sec = tv.tv_sec;
sec = sec + 60*60*BEIJINGTIME;
usec = tv.tv_usec;
//年
yy = sec/(60*60*24*(365*4+1)/4) + 1970;
//日
dd = sec/(60*60*24) - ((yy - 1970)*365 + (yy - 1968)/4);
//月
if(0 == yy%1000)
{
if(0 == (yy/1000)%4)
{
m[1] = 29;
}
}
else
{
if(0 == yy%4)
{
m[1] = 29;
}
}
for(i = 1; i <= 12; i++)
{
if(dd - m[i] < 0)
{
break;
}
else
{
dd = dd -m[i];
}
}
mm = i;
//小时
hh = sec/(60*60)%24;
//分
mi = sec/60 - sec/(60*60)*60;
//秒
ss = sec - sec/60*60;
ms = usec;
printf("%d-%02d-%02d %02d:%02d:%02d.%06d/n", yy, mm, dd, hh, mi, ss, ms);
return 1;
}
执行结果开起来也没问题;
2009-11-27 12:37:38.435576
乍一看,程序似乎没有什么问题,仔细看上面的程序,却有很多疏漏,由于对闰年的考虑不够周全,当时间到达每年年初在某段时间内会出现年和天的取值错误问题,当然,我这个程序只是做出来玩玩,不一定有多大用处,但把程序做的离完美一点不是坏事。
考虑闰年的计算修改程序如下:
#include <stdio.h>
#include <string.h>
#include <sys/time.h>
#define BEIJINGTIME 8
#define DAY (60*60*24)
#define YEARFIRST 2001
#define YEARSTART (365*(YEARFIRST-1970) + 8)
#define YEAR400 (365*4*100 + (4*(100/4 - 1) + 1))
#define YEAR100 (365*100 + (100/4 - 1))
#define YEAR004 (365*4 + 1)
#define YEAR001 365
/*
取当前时间,精确到微秒;
*/
int main(int argc, char *argv[])
{
struct timeval tv;
long sec = 0, usec = 0;
int yy = 0, mm = 0, dd = 0, hh = 0, mi = 0, ss = 0, ms = 0;
int ad = 0;
int y400 = 0, y100 = 0, y004 = 0, y001 = 0;
int m[12] = {31, 28, 31, 30, 31, 30, 31, 31, 30, 31, 30, 31};
int i;
memset(&tv, 0, sizeof(timeval));
gettimeofday(&tv, NULL);
sec = tv.tv_sec;
usec = tv.tv_usec;
sec = sec + (60*60)*BEIJINGTIME;
ad = sec/DAY;
ad = ad - YEARSTART;
y400 = ad/YEAR400;
y100 = (ad - y400*YEAR400)/YEAR100;
y004 = (ad - y400*YEAR400 - y100*YEAR100)/YEAR004;
y001 = (ad - y400*YEAR400 - y100*YEAR100 - y004*YEAR004)/YEAR001;
yy = y400*4*100 + y100*100 + y004*4 + y001*1 + YEARFIRST;
dd = (ad - y400*YEAR400 - y100*YEAR100 - y004*YEAR004)%YEAR001;
//月 日
if(0 == yy%1000)
{
if(0 == (yy/1000)%4)
{
m[1] = 29;
}
}
else
{
if(0 == yy%4)
{
m[1] = 29;
}
}
for(i = 1; i <= 12; i++)
{
if(dd - m[i] < 0)
{
break;
}
else
{
dd = dd -m[i];
}
}
mm = i;
//小时
hh = sec/(60*60)%24;
//分
mi = sec/60 - sec/(60*60)*60;
//秒
ss = sec - sec/60*60;
ms = usec;
printf("%d-%02d-%02d %02d:%02d:%02d.%06d/n", yy, mm, dd, hh, mi, ss, ms);
return 1;
}
到目前为止,我觉得没有问题了。
以上程序仅供娱乐。如果问题,欢迎指正。
今天闲来无事,决定做个小程序,把刚写的程序中用到的gettimeofday函数取出的时间,转换成标准的时间格式(YYYY-MM-DD HH24:MI:SS.USEC),很快把程序做出来了。
#include <stdio.h>
#include <sys/time.h>
//typedef long long Int64;
#define BEIJINGTIME 8;
main()
{
struct timeval tv;
struct timezone tz;
long tm = 0;
long sec = 0, usec = 0;
int yy = 0, mm = 0, dd = 0, hh = 0, mi = 0, ss = 0, ms =0;
int m[12] = {31, 28, 31, 30, 31, 30, 31, 31, 30, 31, 30, 31};
int i;
gettimeofday(&tv, &tz);
sec = tv.tv_sec;
sec = sec + 60*60*BEIJINGTIME;
usec = tv.tv_usec;
//年
yy = sec/(60*60*24*(365*4+1)/4) + 1970;
//日
dd = sec/(60*60*24) - ((yy - 1970)*365 + (yy - 1968)/4);
//月
if(0 == yy%1000)
{
if(0 == (yy/1000)%4)
{
m[1] = 29;
}
}
else
{
if(0 == yy%4)
{
m[1] = 29;
}
}
for(i = 1; i <= 12; i++)
{
if(dd - m[i] < 0)
{
break;
}
else
{
dd = dd -m[i];
}
}
mm = i;
//小时
hh = sec/(60*60)%24;
//分
mi = sec/60 - sec/(60*60)*60;
//秒
ss = sec - sec/60*60;
ms = usec;
printf("%d-%02d-%02d %02d:%02d:%02d.%06d/n", yy, mm, dd, hh, mi, ss, ms);
return 1;
}
执行结果开起来也没问题;
2009-11-27 12:37:38.435576
乍一看,程序似乎没有什么问题,仔细看上面的程序,却有很多疏漏,由于对闰年的考虑不够周全,当时间到达每年年初在某段时间内会出现年和天的取值错误问题,当然,我这个程序只是做出来玩玩,不一定有多大用处,但把程序做的离完美一点不是坏事。
考虑闰年的计算修改程序如下:
#include <stdio.h>
#include <string.h>
#include <sys/time.h>
#define BEIJINGTIME 8
#define DAY (60*60*24)
#define YEARFIRST 2001
#define YEARSTART (365*(YEARFIRST-1970) + 8)
#define YEAR400 (365*4*100 + (4*(100/4 - 1) + 1))
#define YEAR100 (365*100 + (100/4 - 1))
#define YEAR004 (365*4 + 1)
#define YEAR001 365
/*
取当前时间,精确到微秒;
*/
int main(int argc, char *argv[])
{
struct timeval tv;
long sec = 0, usec = 0;
int yy = 0, mm = 0, dd = 0, hh = 0, mi = 0, ss = 0, ms = 0;
int ad = 0;
int y400 = 0, y100 = 0, y004 = 0, y001 = 0;
int m[12] = {31, 28, 31, 30, 31, 30, 31, 31, 30, 31, 30, 31};
int i;
memset(&tv, 0, sizeof(timeval));
gettimeofday(&tv, NULL);
sec = tv.tv_sec;
usec = tv.tv_usec;
sec = sec + (60*60)*BEIJINGTIME;
ad = sec/DAY;
ad = ad - YEARSTART;
y400 = ad/YEAR400;
y100 = (ad - y400*YEAR400)/YEAR100;
y004 = (ad - y400*YEAR400 - y100*YEAR100)/YEAR004;
y001 = (ad - y400*YEAR400 - y100*YEAR100 - y004*YEAR004)/YEAR001;
yy = y400*4*100 + y100*100 + y004*4 + y001*1 + YEARFIRST;
dd = (ad - y400*YEAR400 - y100*YEAR100 - y004*YEAR004)%YEAR001;
//月 日
if(0 == yy%1000)
{
if(0 == (yy/1000)%4)
{
m[1] = 29;
}
}
else
{
if(0 == yy%4)
{
m[1] = 29;
}
}
for(i = 1; i <= 12; i++)
{
if(dd - m[i] < 0)
{
break;
}
else
{
dd = dd -m[i];
}
}
mm = i;
//小时
hh = sec/(60*60)%24;
//分
mi = sec/60 - sec/(60*60)*60;
//秒
ss = sec - sec/60*60;
ms = usec;
printf("%d-%02d-%02d %02d:%02d:%02d.%06d/n", yy, mm, dd, hh, mi, ss, ms);
return 1;
}
到目前为止,我觉得没有问题了。
以上程序仅供娱乐。如果问题,欢迎指正。
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