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c#中如何将dgv中的数据导出

2011-05-14 10:13 375 查看

在c#中如何将dataGridView中的数据导出,可以写出以下代码直接调用
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/// <summary>
/// 将 DataGridView的数据导出Excel
/// </summary>
/// <remarks>
/// using System.IO;
/// </remarks>
/// <param name="dgv"></param>
public static void DataGridViewToExcel(bxyztSkin.Editors.CDataGridView dgv)
{
SaveFileDialog dlg = new SaveFileDialog();
dlg.Filter = "Execl files (*.xls)|*.xls";
dlg.CheckFileExists = false;
dlg.CheckPathExists = false;
dlg.FilterIndex = 0;
dlg.RestoreDirectory = true;
dlg.CreatePrompt = true;
dlg.Title = "保存为Excel文件";
dlg.FileName = DateTime.Now.Ticks.ToString().Trim();

if (dlg.ShowDialog() == DialogResult.OK)
{
Stream myStream;
myStream = dlg.OpenFile();
StreamWriter sw = new StreamWriter(myStream, System.Text.Encoding.GetEncoding(-0));
string columnTitle = "";
try
{
//写入列标题
for (int i = 0; i < dgv.ColumnCount; i++)
{
if (i > 0)
{
columnTitle += "\t";
}
columnTitle += dgv.Columns[i].HeaderText;
}
sw.WriteLine(columnTitle);

//写入列内容
for (int j = 0; j < dgv.Rows.Count; j++)
{
string columnValue = "";
for (int k = 0; k < dgv.Columns.Count; k++)
{
if (k > 0)
{
columnValue += "\t";
}
if (dgv.Rows[j].Cells[k].Value == null)
columnValue += "";
else
columnValue += dgv.Rows[j].Cells[k].Value.ToString().Trim();
}
sw.WriteLine(columnValue);
}
sw.Close();
myStream.Close();
}
catch (Exception e)
{
MessageBox.Show(e.ToString());
}
finally
{
sw.Close();
myStream.Close();
}
}
}
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