C# graphicspath 翻转

C#中GraphicsPath旋转问题（发现网上与此相关的资料很少，我是从一个英文网站上找到的方法，具体原理还不是很明白，写出来大家分享一下）

准备：新建一窗体，添加一个PictureBox和一个btn

功能：点击btn实现图像翻转

备注：我用的是png格式的图

代码：

using System;
using System.Collections.Generic;
using System.ComponentModel;
using System.Data;
using System.Drawing;
using System.Text;
using System.Windows.Forms;
using System.Drawing.Drawing2D;

namespace pathflip
{
public partial class Form1 : Form
{
private GraphicsPath path;

public Form1()
{
InitializeComponent();
}

private void button1_Click(object sender, EventArgs e)
{
Image image = this.pictureBox1.Image;
image.RotateFlip(RotateFlipType.Rotate180FlipY);
this.pictureBox1.Image = image;
Matrix matrix = new Matrix(-1, 0, 0, 1, image.Width, 0);
this.path.Transform(matrix);
this.pictureBox1.Region = new Region(this.path);
}

private void Form1_Load(object sender, EventArgs e)
{
Bitmap bmp = (Bitmap)this.pictureBox1.Image;
this.path = this.CalculateGrahicsPath(bmp);
this.pictureBox1.Region = new Region(this.path);

}
private GraphicsPath CalculateGrahicsPath(Bitmap bitmap)//Region设定前，Graphicpaths获取函数
{
int iWidth = bitmap.Width;
int iHeight = bitmap.Height;
GraphicsPath graphicpath = new GraphicsPath();
System.Drawing.Color color;
for (int row = 0; row < iHeight; row++)
for (int wid = 0; wid < iWidth; wid++)
{
color = bitmap.GetPixel(wid, row);
//if (255 == color.A)
if (255 == color.A)
graphicpath.AddRectangle(new Rectangle(wid, row, 1, 1));

}

return graphicpath;
}
}
}