Hibernate 用原生sql 方式

方式一：

String sql="select fi.id, fi.name FROM meeting_fee_item mfi,fee_item fi " +

"where fi.id=mfi.feeitemid and mfi.id=" + meetingFeeItemId;

Session session = getSessionFactory().getCurrentSession();

Query query=session.createSQLQuery(sql);

List alist= query.list();

List<FeeItem> list = new ArrayList<FeeItem>();

if (alist != null && alist.size() > 0) {

for (int i = 0; i < alist.size(); i++) {

Object[] objects = (Object[]) alist.get(i);

FeeItem feeItem = new FeeItem();

feeItem.setId((Integer) objects[0]); // id必须的

feeItem.setName((String) objects[1]); 相对应的配置所查询的字段，如fi.id,f.name，有多少个，就相应配

System.out.println("object: "+(String) objects[1]);

list.add(feeItem);

}

}

return list;

}

解决了类型转换异常问题。。

方式二：

回调模式

public Object doInHibernate(Session session)

throws HibernateException, SQLException {

String sql = "select *,d.roomNo as roomNo from (select a.id,a.name,a.zwu,b.name as unitsName,b.address,b.zip,a.phone,a.mail,a.cellphone from user a,units b where a.unitsId=b.id ";

if (unitsTypeId != null && unitsTypeId != 0) {

sql += " and b.unitstypeid=" + unitsTypeId;

}

sql += " ) c left join register d on c.id=d.userid ";

SQLQuery q = session.createSQLQuery(sql).addScalar("name",

Hibernate.STRING).addScalar("zwu", Hibernate.STRING)

.addScalar("unitsName", Hibernate.STRING).addScalar(

"address", Hibernate.STRING).addScalar("zip",

Hibernate.STRING).addScalar("phone",

Hibernate.STRING).addScalar("mail",

Hibernate.STRING).addScalar("cellphone",

Hibernate.STRING).addScalar("roomNo",

Hibernate.STRING);

。。。。

下面进行类型转换，大致如上一。