python 身份证校验位计算

以后可能用得到

# -*- coding:gbk -*-
#S+=Sum(Ai*Wi);
#Ti[S%11]
import sys

class IdentityCard:
def __init__( self ):
self.__Wi = [7, 9, 10, 5, 8, 4, 2, 1, 6, 3, 7, 9, 10, 5, 8, 4, 2]
self.__Ti = ['1', '0', 'x', '9', '8', '7', '6', '5', '4', '3', '2']

def check( self, code ):
if (len(code) != 17):
print "必须为17位的字符"
return False
return True

def calculate( self, code ):
sum = 0
for i in range(17):
sum += int(code[i])*self.__Wi[i]
return self.__Ti[sum%11]

def test():
ic = IdentityCard()
code = "33000000000000000" #17位身份证
if ic.check(code):
print "你的校验位为:%s"%ic.calculate(code)

if __name__ == '__main__':
test()