sicily 1020 高精度求余

#include <iostream>
#include <string>
using namespace std;
int main()
{
int cs;
cin>>cs;
while(cs--)
{
int n;
cin>>n;
int nr[100],i;
for ( i=0;i<n;i++)
{
cin>>nr[i];
}
string LNum;
cin>>LNum;
int j=0;
cout<<"(";
for (i=0;i<n;i++)
{
int store=0;
for (j=0;j<LNum.size();j++)
{
store=store*10+(LNum[j]-'0');
if (store>=nr[i])
{
store=store%nr[i];
}
}
if (i==n-1)
{
cout<<store<<")"<<endl;
}
else
{
cout<<store<<",";
}
}
}
return 0;
}