通过AWK脚本解析海量文本攫取十六进制字符串转为点分十进制信息

首先要说明的一点是，在linux下面有现成的awk函数strtonum()函数可用，该函数可以把字符串转为10进制的数，但是在windows下面，mingw中的awk好像不支持strtonum函数，故而想起了一下的笨方法，希望大家批评指正！

# !/bin/awk
# Description: It's a awk script to convert the hex number to decimal

# Name: str2num.awk
# Autor: Lihan
# Data: 2011-02-19

function char2num(char) {
dec = "0123456789"; # decimal
cap = "ABCDEF"; # capital
min = "abcdef"; # minuscule
if( length(char) > 1 ){
print "the length of the input char is erro!";
return;
}
if( index(dec,char) > 0 ) {
return (index(dec,char) - 1);
}
if( index(cap,char) > 0 ) {
return (index(cap,char) + 9);
}
if( index(min,char) > 0 ) {
return (index(min,char) + 9);
}
print "input char error!"
}

function str2num(str,out) {
split(str,out,"");
return;
}

BEGIN {
#print "##############################################";
#print " BEGIN TO CONVERT" ;
#print "##############################################";
}

/.*/ { #这里的匹配模式和自己的文本对应起来
len = length($1); # Get the length of the hex string
str2num($1,out);
}

END {
printf("%d.%d.%d.%d",char2num(out[1])*16 + char2num(out[2]),
char2num(out[3])*16 + char2num(out[4]),
char2num(out[5])*16 + char2num(out[6]),
char2num(out[7])*16 + char2num(out[8]));
}

-----------------------------------

测试结果如下：

hail@HAIL-PC ~/awk
$ echo "C0A0B0C00" | awk -f str2num.awk
192.160.176.19