ural 1001 Reverse Root
2011-01-30 12:21
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水题一道. 沉默.
]#include<iostream> #include<cmath> __int64 A[700000]; int main() { int i=0; while( scanf("%I64d",&A[i++])!=EOF ) {} i--; while( i-- ) printf("%.4lf/n",sqrt((double)A[i])); return 0; }
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