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UVa OJ 401-Palindromes

2011-01-13 15:18 267 查看
简单字符串处理:

{
Author:wzx961008
Problem:UVa 401-Palindromes
Verdict:Accepted
Language:PASCAL
Run Time:0.024s
Submission Date:2011-01-12 01:05:27
}
const mirrorchar1:string='ABCDEFGHIJKLMNOPQRSTUVWXYZ123456789';
mirrorchar2:string='A   3  HIL JM O   2TUVWXY51SE Z  8 ';
var s,s1:string;
i:longint;
ifpalindrome,ifmirror:boolean;
function mirror(c1,c2:char):boolean;
begin
if pos(c1,mirrorchar1)=pos(c2,mirrorchar2) then exit(true);
mirror:=false;
end;
begin
while not eof do begin
readln(s);
s1:='';
for i:=1 to length(s) do s1:=s[i]+s1;
ifpalindrome:=false;
if s1=s then ifpalindrome:=true;
ifmirror:=true;
for i:=1 to length(s) do
ifmirror:=ifmirror and mirror(s[i],s1[i]);
if (ifpalindrome)and(ifmirror) then writeln(s,' -- is a mirrored palindrome.')
else if ifpalindrome then writeln(s,' -- is a regular palindrome.')
else if ifmirror then writeln(s,' -- is a mirrored string.')
else writeln(s,' -- is not a palindrome.');
writeln;
end;
end.
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