sql 判断两个字符串是否存在相同的内容

-- =============================================
-- Author: wuchaorang
-- Create date: 2010-12-22
-- Description: 判斷兩個字符串是否存在相同的內容(查找@newSplit中是否有相同的字符串存在于@orginSplit中)
-- Debug:select dbo.fun_charindex('a,b,c,d','d',',') or select dbo.fun_charindex('a,b,c','b,',',')
--返回: 存在返回1,否則返回0
-- =============================================
ALTER function fun_charindex
(
@orginSplit varchar(4000),--原始值
@newSplit varchar(4000),--需要判斷的值
@speaterString varchar(20)--分隔符
)
returns smallint
as
begin
declare @val smallint,@i int,@helpSplit varchar(4000)
set @val=0
set @newSplit=rtrim(ltrim(@newSplit))
set @speaterString=rtrim(ltrim(@speaterString))
set @orginSplit=rtrim(ltrim(@orginSplit))
if left(@orginSplit,len(@speaterString))<>@speaterString
set @orginSplit=@speaterString+@orginSplit
if right(@orginSplit,len(@speaterString))<>@speaterString
set @orginSplit=@orginSplit+@speaterString
if @newSplit=''
return @val
if charindex(@speaterString,@newSplit)=0
begin
--或者改成set @helpSplit=replace(@orginSplit,@speaterString+@newSplit+@speaterString,'')
-- if len(@speaterString+@newSplit+@speaterString)+len(@helpSplit)=len(@orginSplit)
set @helpSplit=@speaterString+@newSplit+@speaterString
if patindex('%'+@helpSplit+'%',@orginSplit)>0
set @val=1
end
else
begin
if right(@newSplit,len(@speaterString))<>@speaterString
set @newSplit=@newSplit+@speaterString
set @i=charindex(@speaterString,@newSplit)
while @i>0
begin
if rtrim(ltrim(left(@newSplit,@i-1)))=''
begin
set @newSplit=SUBSTRING(@newSplit,@i+1,LEN(@newSplit)-@i)
set @i=CHARINDEX(@speaterString,@newSplit)
continue
end
set @helpSplit=@speaterString+rtrim(ltrim(left(@newSplit,@i-1)))+@speaterString
--或者改成 len(@helpSplit)+len(replace(@orginSplit,@helpSplit,''))=len(@orginSplit)
if patindex('%'+@helpSplit+'%',@orginSplit)>0
begin
set @val=1
break
end
set @newSplit=SUBSTRING(@newSplit,@i+1,LEN(@newSplit)-@i)
set @i=CHARINDEX(@speaterString,@newSplit)
end
end
return @val
end


实例：
select dbo.fun_charindex('aa,bb,cc,dd','b,b,cc',',') 存在则返回1，否则返回0