C语言实现字符串的简单匹配

/*
* main.c
* 简单的字符串匹配
* Created on: Nov 6, 2010
* Author: jenson
*/

#include <stdio.h>
#include <stdlib.h>

#define N 10000

/**
* src:源字符串，str：所要匹配的字符串
*/
int search(const char*src, const char *str);

int main() {
int pos = search("bbabcaaabbb","abc");
printf("pos=%d\n",pos);
}

int search(const char*src, const char *str) {
int src_len = strlen(src);
int str_len = strlen(str);
if (src_len < str_len) {
return -1;
}
int i,j, pos = -1;
for(i = 0;src[i]!='\0';i++){
for(j=0;str[j]!='\0';j++){
if(src[i+j]!=str[j]){
break;
}
}
if(str[j] == 0){
return i;
}
}
}