Hibernate:继承映射“Could not format discriminator”错误解决
2010-10-29 14:27
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文章出处: http://www.web158.com/web_list_content.asp?id=16257
借助于Hibernate强大的O/R Mapping能力,我们能够通过discriminator轻易地将一颗继承树映射到一个表中,通过discriminator确定具体映射的子类。
在设置@hibernate.discriminator column="type" type="integer"后,启动Hibernate报错:
Could not format discriminator value to SQL string
搜索Hibernate官方文档后发现问题,原来Hibernate默认的discriminator的type是String,当设置discriminator的type为integer后,需要为父类也设置@hibernate.class table="TABLE_NAME" discriminator-value="not null",否则,Hibernate默认的discriminator-value是完整的类名,在转换String到int时造成NumberFormatException。
最后运行XDoclet,生成hbm文件:
"-//Hibernate/Hibernate Mapping DTD 3.0//EN"
"http://hibernate.sourceforge.net/hibernate-mapping-3.0.dtd">
借助于Hibernate强大的O/R Mapping能力,我们能够通过discriminator轻易地将一颗继承树映射到一个表中,通过discriminator确定具体映射的子类。
在设置@hibernate.discriminator column="type" type="integer"后,启动Hibernate报错:
Could not format discriminator value to SQL string
搜索Hibernate官方文档后发现问题,原来Hibernate默认的discriminator的type是String,当设置discriminator的type为integer后,需要为父类也设置@hibernate.class table="TABLE_NAME" discriminator-value="not null",否则,Hibernate默认的discriminator-value是完整的类名,在转换String到int时造成NumberFormatException。
最后运行XDoclet,生成hbm文件:
"-//Hibernate/Hibernate Mapping DTD 3.0//EN"
"http://hibernate.sourceforge.net/hibernate-mapping-3.0.dtd">
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