Java is Pass-by-Value!
2010-10-17 15:02
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IntroductionPass-by-valueThe actual parameter (or argument expression) is fully evaluated and the resulting value is copied into a location being used to hold the formal parameter's value during method/function execution. That location is typically a chunk of memory on the runtime stack for the application (which is how Java handles it), but other languages could choose parameter storage differently. Pass-by-reference The formal parameter merely acts as an alias for the actual parameter. Anytime the method/function uses the formal parameter (for reading or writing), it is actually using the actual parameter. Java is strictly pass-by-value, exactly as in C. Read the Java Language Specification (JLS). It's spelled out, and it's correct. In http://java.sun.com/docs/books/jls/third_edition/html/classes.html#8.4.1: When the method or constructor is invoked (15.12), the values of the actual argument expressions initialize newly created parameter variables, each of the declared Type, before execution of the body of the method or constructor. TheIdentifier that appears in the DeclaratorId may be used as a simple name in the body of the method or constructor to refer to the formal parameter. [In the above, values is my emphasis, not theirs] In short: Java has pointers and is strictly pass-by-value. There's no funky rules. It's simple, clean, and clear. (Well, as clear as the evil C++-like syntax will allow ;) Note: See the note at the end of this article for the semantics of remote method invocation (RMI). What is typically called "pass by reference" for remote objects is actually incredibly bad semantics. TheThere's |
Figure 1: (Non-Java) Basic swap function structure |
swap(Type arg1, Type arg2) { Type temp = arg1; arg1 = arg2; arg2 = temp; } |
you can write such a method/function in your language such that
calling
Figure 2: (Non-Java) Calling the swap function |
Type var1 = ...; Type var2 = ...; swap(var1,var2); |
switches the values of the variables var1 and var2, the language
supports pass-by-reference semantics.
For
example, in Pascal, you can write
Figure 3: (Pascal) Swap function |
procedure swap(var arg1, arg2: SomeType); var temp : SomeType; begin temp := arg1; arg1 := arg2; arg2 := temp; end; ... { in some other procedure/function/program } var var1, var2 : SomeType; begin var1 := ...; { value "A" } var2 := ...; { value "B" } swap(var1, var2); { now var1 has value "B" and var2 has value "A" } end; |
in C++ you could write
Figure 4: (C++) Swap function |
void swap(SomeType& arg1, Sometype& arg2) { SomeType temp = arg1; arg1 = arg2; arg2 = temp; } ... SomeType var1 = ...; // value "A" SomeType var2 = ...; // value "B" swap(var1, var2); // swaps their values! // now var1 has value "B" and var2 has value "A" |
let me know if my Pascal or C++ has lapsed and I've messed up the
syntax...)
But
you cannot do this in Java!
Now
the details...
Theproblem we're facing here is statements like
In
Java, Objects are passed by reference, and primitives are passed by
value.
This
is half incorrect. Everyone can easily agree that primitives are
passed by value; there's no such thing in Java as a pointer/reference
to a primitive.
However,
Objects are not passed by reference. A correct statement would
be Object references are passed by value.
This
may seem like splitting hairs, bit it is far from it. There is
a world of difference in meaning. The following examples should help
make the distinction.
In
Java, take the case of
Figure 5: (Java) Pass-by-value example |
public void foo(Dog d) { d = new Dog("Fifi"); // creating the "Fifi" dog } Dog aDog = new Dog("Max"); // creating the "Max" dog // at this point, aDog points to the "Max" dog foo(aDog); // aDog still points to the "Max" dog |
variable passed in (aDog) is not modified! After
calling foo, aDog still points to the "Max"
Dog!
Many
people mistakenly think/state that something like
Figure 6: (Java) Still pass-by-value... |
public void foo(Dog d) { d.setName("Fifi"); } |
that Java does in fact pass objects by reference.
The
mistake they make is in the definition of
Figure 7: (Java) Defining a Dog pointer |
Dog d; |
When you write that definition, you are defining a pointer to
a Dog object, not a Dog object itself.
On
Pointers versus References...
Theproblem here is that the folks at Sun made a naming mistake.
In
programming language design, a "pointer" is a variable that
indirectly tracks the location of some piece of data. The value of a
pointer is often the memory address of the data you're interested in.
Some languages allow you to manipulate that address; others do not.
A
"reference" is an alias to another variable. Any
manipulation done to the reference variable directly changes the
original variable.
Check
out the second sentence of
http://java.sun.com/docs/books/jls/third_edition/html/typesValues.html#4.3.1.
"The
reference values (often just references)
are pointers
to
these objects, and a special null reference, which refers to no
object"
They
emphasize "pointers" in their description... Interesting...
When
they originally were creating Java, they had "pointer" in
mind (you can see some remnants of this in things like
NullPointerException).
Sun
wanted to push Java as a secure language, and one of Java's
advantages was that it does not allow pointer arithmetic as C++ does.
They
went so far as to try a different name for the concept, formally
calling them "references". A big mistake and it's caused
even more confusion in the process.
There's
a good explanation of reference variables at
http://www.cprogramming.com/tutorial/references.html.
(C++ specific, but it says the right thing about the concept of a
reference variable.)
The
word "reference" in programming language design originally
comes from how you pass data to
subroutines/functions/procedures/methods. A reference parameter is an
alias to a variable passed as a parameter.
In
the end, Sun made a naming mistake that's caused confusion. Java has
pointers, and if you accept that, it makes the way Java behaves make
much more sense.
Calling
Methods
CallingFigure 8: (Java) Passing a pointer by value |
foo(d); |
the value of d to foo; it does not pass the object that
d points to!
The
value of the pointer being passed is similar to a memory address.
Under the covers it may be a tad different, but you can think of it
in exactly the same way. The value uniquely identifies some object on
the heap.
However,
it makes no difference how pointers are implemented
under the covers. You program with them exactly the
same way in Java as you would in C or C++. The syntax is just
slightly different (another poor choice in Java's design; they should
have used the same -> syntax for de-referencing as C++).
In
Java,
Figure 9: (Java) A pointer |
Dog d; |
exactly like C++'s
Figure 10: (C++) A pointer |
Dog *d; |
using
Figure 11: (Java) Following a pointer and calling a method |
d.setName("Fifi"); |
exactly like C++'s
Figure 12: (C++) Following a pointer and calling a method |
d->setName("Fifi"); |
sum up: Java has pointers, and the value
of the pointer is passed in. There's no way to actually
pass an object itself as a parameter. You can only pass a pointer to
an object.
Keep
in mind, when you call
Figure 13: (Java) Even more still passing a pointer by value |
foo(d); |
not passing an object; you're passing a pointer to the object.
For
a slightly different (but still correct) take on this issue, please
see http://www-106.ibm.com/developerworks/library/j-praxis/pr1.html.
It's from Peter Haggar's excellent book, Practical
Java.)
A
Note on Remote Method Invocation (RMI)
Whenpassing parameters to remote methods, things get a bit more complex.
First, we're (usually) dealing with passing data between two
independent virtual machines, which might be on separate physical
machines as well. Passing the value of a pointer wouldn't do any
good, as the target virtual machine doesn't have access to the
caller's heap.
You'll
often hear "pass by value" and "pass by reference"
used with respect to RMI. These terms have more of a "logical"
meaning, and really aren't correct for the intended use.
Here's
what is usually meant by these phrases with regard to RMI. Note that
this is not proper usage of "pass by value" and
"pass by reference" semantics:
RMI
Pass-by-value
The
actual parameter is serialized and passed using a network
protocol to the target remote object. Serialization essentially
"squeezes" the data out of an object/primitive. On the
receiving end, that data is used to build a "clone" of the
original object or primitive. Note that this process can be rather
expensive if the actual parameters point to large objects (or large
graphs of objects).
This isn't quite the right use of
"pass-by-value"; I think it should really be called
something like "pass-by-memento". (See "Design
Patterns" by Gamma et al for a description of the Memento
pattern).
RMI
Pass-by-reference
The
actual parameter, which is itself a remote object, is
represented by a proxy. The proxy keeps track of where the actual
parameter lives, and anytime the target method uses the formal
parameter, another remote method invocation occurs to "call
back" to the actual parameter. This can be useful if the actual
parameter points to a large object (or graph of objects) and there
are few call backs.
This isn't quite the right use of
"pass-by-reference" (again, you cannot change the actual
parameter itself). I think it should be called something like
"pass-by-proxy". (Again, see "Design Patterns"
for descriptions of the Proxy pattern).
Follow
up from stackoverflow.com
Iposted the following as some clarification when a discussion on this
article arose on http://stackoverflow.com.
The
Java Spec says that everything in java is pass-by-value. There is no
such thing as "pass-by-reference" in java.
The
key to understanding this is that something like
Figure 14: (Java) Not a Dog; a pointer to a Dog |
Dog myDog; |
not a Dog; it's actually a pointer to a Dog.
What
that means, is when you have
Figure 15: (Java) Passing the Dog's location |
Dog myDog = new Dog("Rover"); foo(myDog); |
essentially passing the address of the created Dog object to the foo
method. (I say essentially b/c java pointers aren't direct addresses,
but it's easiest to think of them that way)
Suppose
the Dog object resides at memory address 42. This means we pass 42 to
the method.
If
the Method were defined as
Figure 16: (Java) Looking at the called method in detail |
public void foo(Dog someDog) { someDog.setName("Max"); // AAA someDog = new Dog("Fifi"); // BBB someDog.setName("Rowlf"); // CCC } |
look at what's happening.
the
parameter someDog is set to the value 42
at
line "AAA"
someDog
is followed to the Dog it points to (the Dog object at address 42)
that Dog (the one at address 42) is asked to change his name to Max
at
line "BBB"
a
new Dog is created. Let's say he's at address 74 we assign the
parameter someDog to 74
at
line "CCC"
someDog
is followed to the Dog it points to (the Dog object at address 74)
that Dog (the one at address 74) is asked to change his name to
Rowlf then, we return
Now
let's think about what happens outside the method:
Did
myDog change?
There's
the key.
Keeping
in mind that myDog is a pointer, and not an actual Dog, the answer is
NO. myDog still has the value 42; it's still pointing to the original
Dog.
It's
perfectly valid to follow an address and change what's at the end of
it; that does not change the variable, however.
Java
works exactly like C. You can assign a pointer, pass the pointer to a
method, follow the pointer in the method and change the data that was
pointed to. However, you cannot change where that pointer points.
In
C++, Ada, Pascal and other languages that support pass-by-reference,
you can actually change the variable that was passed.
If
Java had pass-by-reference semantics, the foo method we defined above
would have changed where myDog was pointing when it assigned someDog
on line BBB.
Think
of reference parameters as being aliases for the variable passed in.
When that alias is assigned, so is the variable that was passed in.
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