关于多条id相同，只取一条记录得sql语句

sqlserver 2005 中

CREATE TABLE [dbo].[mian](

[id] [int] NOT NULL,

[name] [varchar](50) COLLATE Chinese_PRC_CI_AS NULL,

[age] [int] NULL,

[state] [bit] NOT NULL

)

--执行2遍，则共8条记录

insert into mian values(1,'st',27,1)

insert into mian values(1,'tj',28,0)

insert into mian values(2,'2st',45,0)

insert into mian values(2,'2tj',88,0)

div>
id name age state

1 st 27 1

1 tj 28 0

2 2st 45 0

2 2tj 88 0

1 st 27 1

1 tj 28 0

2 2st 45 0

2 2tj 88 0

执行id有相同，执行有state有1的就取出1的，没有的就取出0中的任何一条

select * from (select * , row_number() over(partition by id order by state desc) as sequence

from mian ) a where sequence =1

--where 前要有个表名，^-^

oracle中要如下修改：

select * from (select t.* , row_number() over(partition by t.id order by t.state desc) as sequence

from mian t ) a where sequence =1

oracle 中要加个别名t，与sqlserver2005中不同，不知道为什么。