Get ColumnLetter by ColumnNumber in Excel with VBA

Function GetColumnLetterByColumnNumber(ColumnNumber As Integer) As String
  If ColumnNumber > 26 Then

    ' 1st character:  Subtract 1 to map the characters to 0-25,
    '                 but you don't have to remap back to 1-26
    '                 after the 'Int' operation since columns
    '                 1-26 have no prefix letter

    ' 2nd character:  Subtract 1 to map the characters to 0-25,
    '                 but then must remap back to 1-26 after
    '                 the 'Mod' operation by adding 1 back in
    '                 (included in the '65')

    ColumnLetter = Chr(Int((ColumnNumber - 1) / 26) + 64) & Chr(((ColumnNumber - 1) Mod 26) + 65)
  Else
    ' Columns A-Z
    ColumnLetter = Chr(ColumnNumber + 64)
  End If
End Function