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Linux下的c程序---数组、malloc

2010-04-16 16:46 218 查看
#include <stdio.h>
#include <stdlib.h>

struct flex
{
int count;
double average;
double scores[]; // 定义可伸缩的数组
}; // 声明结构体

void showFlex(const struct flex * p); //定义函数

int main(void)
{
struct flex * pf1, *pf2;

int n = 5; // 变量的初始化
int i;
int tot = 0;
// allocate space for structure plus array
pf1 = malloc(sizeof(struct flex) + n * sizeof(double)); //根据数组的大小申请地址空间
pf1->count = n;
for (i = 0; i < n; i++)
{
pf1->scores[i] = 20.0 - i; //给数组元素赋值
tot += pf1->scores[i];
}
pf1->average = tot / n;
showFlex(pf1);

n = 9;
tot = 0;
pf2 = malloc(sizeof(struct flex) + n * sizeof(double));
pf2->count = n;
for (i = 0; i < n; i++)
{
pf2->scores[i] = 20.0 - i/2.0;
tot += pf2->scores[i];
}
pf2->average = tot / n;
showFlex(pf2);
free(pf1); //释放地址空间
free(pf2);
return 0;
}

void showFlex(const struct flex * p) //遍历结构体中的数组并打印平均值
{
int i;
printf("Scores : ");
for (i = 0; i < p->count; i++)
printf("%g ", p->scores[i]);
printf("\nAverage: %g\n", p->average);
}
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