不错的SQL面试题(一)
2010-03-09 16:13
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Student(S#,Sname,Sage,Ssex) 学生表
Course(C#,Cname,T#) 课程表
SC(S#,C#,score) 成绩表
Teacher(T#,Tname) 教师表
问题:
1、查询“001”课程比“002”课程成绩高的所有学生的学号;
select a.S#
from (select s#,score
from SC
where C#='001') a,(select
s#,score
from SC
where C#='002') b
where a.score>b.score
and a.s#=b.s#;
2、查询平均成绩大于60分的同学的学号和平均成绩;
select S#,avg(score)
from sc
group
by S# having
avg(score)
>60;
3、查询所有同学的学号、姓名、选课数、总成绩;
select Student.S#,Student.Sname,count(SC.C#),sum(score)
from Student
left
Outer join SC
on Student.S#=SC.S#
group
by Student.S#,Sname
4、查询姓“李”的老师的个数;
select
count(distinct(Tname))
from Teacher
where Tname
like
'李%';
新解:
select count(*) from Teacher where Tname like '李%' 或者 select count(*) from Teacher where left(Tname,1) = '李%'
5、查询没学过“叶平”老师课的同学的学号、姓名;
select Student.S#,Student.Sname
from Student
where S#
not
in (select
distinct( SC.S#)
from SC,Course,Teacher
where SC.C#=Course.C#
and Teacher.T#=Course.T#
and Teacher.Tname='叶平');
6、查询学过“001”并且也学过编号“002”课程的同学的学号、姓名;
select Student.S#,Student.Sname
from Student,SC
where Student.S#=SC.S#
and SC.C#='001'and
exists(
Select *
from SC
as SC_2 where SC_2.S#=SC.S#
and SC_2.C#='002');
7、查询学过“叶平”老师所教的所有课的同学的学号、姓名;
select S#,Sname
from Student
where S#
in (select S#
from SC ,Course ,Teacher
where SC.C#=Course.C#
and Teacher.T#=Course.T#
and Teacher.Tname='叶平'
group
by S# having
count(SC.C#)=(select
count(C#)
from Course,Teacher
where Teacher.T#=Course.T#
and Tname='叶平'));
8、查询课程编号“002”的成绩比课程编号“001”课程低的所有同学的学号、姓名;
Select S#,Sname
from (select Student.S#,Student.Sname,score ,(select
score from SC SC_2
where SC_2.S#=Student.S#
and SC_2.C#='002')
score2
from Student,SC
where Student.S#=SC.S#
and C#='001')
S_2 where score2
<score;
9、查询所有课程成绩小于60分的同学的学号、姓名;
select S#,Sname
from Student
where S#
not in (select Student.S#
from Student,SC
where S.S#=SC.S#
and score>60);
10、查询没有学全所有课的同学的学号、姓名;
select Student.S#,Student.Sname
from Student,SC
where Student.S#=SC.S#
group
by Student.S#,Student.Sname
having
count(C#) <(select
count(C#)
from Course);
11、查询至少有一门课与学号为“1001”的同学所学相同的同学的学号和姓名;
select S#,Sname
from Student,SC
where Student.S#=SC.S#
and C#
in select C#
from SC
where S#='1001';
12、查询至少学过学号为“001”同学所有一门课的其他同学学号和姓名;
select
distinct SC.S#,Sname
from Student,SC
where Student.S#=SC.S#
and C#
in (select C#
from SC
where S#='001');
13、把“SC”表中“叶平”老师教的课的成绩都更改为此课程的平均成绩;
update SC
set score=(select
avg(SC_2.score)
from SC SC_2
where SC_2.C#=SC.C# )
from Course,Teacher
where Course.C#=SC.C#
and Course.T#=Teacher.T#
and Teacher.Tname='叶平');
14、查询和“1002”号的同学学习的课程完全相同的其他同学学号和姓名;
select S#
from SC
where C# in (select C#
from SC
where S#='1002')
group
by S# having
count(*)=(select
count(*)
from SC
where S#='1002');
15、删除学习“叶平”老师课的SC表记录;
Delect SC
from course ,Teacher
where Course.C#=SC.C#
and Course.T#= Teacher.T#
and Tname='叶平';
16、向SC表中插入一些记录,这些记录要求符合以下条件:没有上过编号“003”课程的同学学号、2、
号课的平均成绩;
Insert SC
select S#,'002',(Select
avg(score)
from SC
where C#='002')
from Student
where S#
not in (Select S#
from SC
where C#='002');
17、按平均成绩从高到低显示所有学生的“数据库”、“企业管理”、“英语”三门的课程成绩,按如下形式显示: 学生ID,,数据库,企业管理,英语,有效课程数,有效平均分
SELECT S#
as 学生ID
,(SELECT score
FROM SC
WHERE SC.S#=t.S#
AND C#='004')
AS 数据库
,(SELECT score
FROM SC
WHERE SC.S#=t.S#
AND C#='001')
AS 企业管理
,(SELECT score
FROM SC
WHERE SC.S#=t.S#
AND C#='006')
AS 英语
,COUNT(*)
AS 有效课程数,
AVG(t.score)
AS 平均成绩
FROM SC
AS t
GROUP
BY S#
ORDER
BY avg(t.score)
18、查询各科成绩最高和最低的分:以如下形式显示:课程ID,最高分,最低分
SELECT L.C#
As 课程ID,L.score
AS 最高分,R.score
AS 最低分
FROM SC L ,SC
AS R
WHERE L.C#
= R.C#
and
L.score = (SELECT
MAX(IL.score)
FROM SC
AS IL,Student
AS IM
WHERE L.C#
= IL.C#
and IM.S#=IL.S#
GROUP
BY IL.C#)
AND
R.Score = (SELECT
MIN(IR.score)
FROM SC
AS IR
WHERE R.C#
= IR.C#
GROUP
BY IR.C#
);
19、按各科平均成绩从低到高和及格率的百分数从高到低顺序
SELECT t.C#
AS 课程号,max(course.Cname)AS 课程名,isnull(AVG(score),0)
AS 平均成绩
,100
* SUM(CASE
WHEN
isnull(score,0)>=60
THEN
1
ELSE
0
END)/COUNT(*)
AS 及格百分数
FROM SC T,Course
where t.C#=course.C#
GROUP
BY t.C#
ORDER
BY 100
* SUM(CASE
WHEN
isnull(score,0)>=60
THEN
1
ELSE
0
END)/COUNT(*)
DESC
20、查询如下课程平均成绩和及格率的百分数(用"1行"显示): 企业管理(001),马克思(002),OO&UML
(003),数据库(004)
SELECT
SUM(CASE
WHEN C#
='001'
THEN score
ELSE 0
END)/SUM(CASE
C# WHEN
'001'
THEN
1
ELSE
0
END)
AS 企业管理平均分
,100
* SUM(CASE
WHEN C#
= '001'
AND score
>= 60
THEN
1
ELSE
0
END)/SUM(CASE
WHEN C#
= '001'
THEN
1
ELSE
0
END)
AS 企业管理及格百分数
,SUM(CASE
WHEN C#
= '002'
THEN score
ELSE 0
END)/SUM(CASE
C# WHEN
'002'
THEN
1
ELSE
0
END)
AS 马克思平均分
,100
* SUM(CASE
WHEN C#
= '002'
AND score
>= 60
THEN
1
ELSE
0
END)/SUM(CASE
WHEN C#
= '002'
THEN
1
ELSE
0
END)
AS 马克思及格百分数
,SUM(CASE
WHEN C#
= '003'
THEN score
ELSE 0
END)/SUM(CASE
C# WHEN
'003'
THEN
1
ELSE
0
END)
AS UML平均分
,100
* SUM(CASE
WHEN C#
= '003'
AND score
>= 60
THEN
1
ELSE
0
END)/SUM(CASE
WHEN C#
= '003'
THEN
1
ELSE
0
END)
AS UML及格百分数
,SUM(CASE
WHEN C#
= '004'
THEN score
ELSE 0
END)/SUM(CASE
C# WHEN
'004'
THEN
1
ELSE
0
END)
AS 数据库平均分
,100
* SUM(CASE
WHEN C#
= '004'
AND score
>= 60
THEN
1
ELSE
0
END)/SUM(CASE
WHEN C#
= '004'
THEN
1
ELSE
0
END)
AS 数据库及格百分数
FROM SC
21、查询不同老师所教不同课程平均分从高到低显示
SELECT
max(Z.T#) AS 教师ID,MAX(Z.Tname)
AS 教师姓名,C.C#
AS 课程ID,MAX(C.Cname)
AS 课程名称,AVG(Score)
AS 平均成绩
FROM SC
AS T,Course
AS C ,Teacher
AS Z
where T.C#=C.C#
and C.T#=Z.T#
GROUP
BY C.C#
ORDER
BY AVG(Score)
DESC
22、查询如下课程成绩第
3 名到第
6 名的学生成绩单:企业管理(001),马克思(002),UML
(003),数据库(004)
[学生ID],[学生姓名],企业管理,马克思,UML,数据库,平均成绩
SELECT
DISTINCT
top 3
SC.S# As 学生学号,
Student.Sname AS 学生姓名 ,
T1.score AS 企业管理,
T2.score AS 马克思,
T3.score AS UML,
T4.score AS 数据库,
ISNULL(T1.score,0)
+ ISNULL(T2.score,0)
+ ISNULL(T3.score,0)
+ ISNULL(T4.score,0)
as 总分
FROM Student,SC
LEFT
JOIN SC AS T1
ON SC.S#
= T1.S#
AND T1.C# =
'001'
LEFT
JOIN SC
AS T2
ON SC.S#
= T2.S#
AND T2.C# =
'002'
LEFT
JOIN SC
AS T3
ON SC.S#
= T3.S#
AND T3.C# =
'003'
LEFT
JOIN SC
AS T4
ON SC.S#
= T4.S#
AND T4.C# =
'004'
WHERE student.S#=SC.S#
and
ISNULL(T1.score,0)
+ ISNULL(T2.score,0)
+ ISNULL(T3.score,0)
+ ISNULL(T4.score,0)
NOT
IN
(SELECT
DISTINCT
TOP
15
WITH TIES
ISNULL(T1.score,0)
+ ISNULL(T2.score,0)
+ ISNULL(T3.score,0)
+ ISNULL(T4.score,0)
FROM sc
LEFT
JOIN sc
AS T1
ON sc.S#
= T1.S#
AND T1.C# =
'k1'
LEFT
JOIN sc
AS T2
ON sc.S#
= T2.S#
AND T2.C# =
'k2'
LEFT
JOIN sc
AS T3
ON sc.S#
= T3.S#
AND T3.C# =
'k3'
LEFT
JOIN sc
AS T4
ON sc.S#
= T4.S#
AND T4.C# =
'k4'
ORDER
BY ISNULL(T1.score,0)
+ ISNULL(T2.score,0)
+ ISNULL(T3.score,0)
+ ISNULL(T4.score,0)
DESC);
23、统计列印各科成绩,各分数段人数:课程ID,课程名称,[100-85],[85-70],[70-60],[
<60]
SELECT SC.C#
as 课程ID, Cname
as 课程名称
,SUM(CASE
WHEN score
BETWEEN 85
AND
100
THEN
1
ELSE
0
END)
AS [100 - 85]
,SUM(CASE
WHEN score
BETWEEN 70
AND
85
THEN
1
ELSE
0
END)
AS [85 - 70]
,SUM(CASE
WHEN score
BETWEEN 60
AND
70
THEN
1
ELSE
0
END)
AS [70 - 60]
,SUM(CASE
WHEN score
< 60
THEN
1
ELSE
0
END)
AS [60 -]
FROM SC,Course
where SC.C#=Course.C#
GROUP
BY SC.C#,Cname;
24、查询学生平均成绩及其名次
SELECT
1+(SELECT
COUNT(
distinct 平均成绩)
FROM (SELECT S#,AVG(score)
AS 平均成绩
FROM SC
GROUP
BY S#
) AS T1
WHERE 平均成绩
> T2.平均成绩)
as 名次,
S# as 学生学号,平均成绩
FROM (SELECT S#,AVG(score) 平均成绩
FROM SC
GROUP
BY S#
) AS T2
ORDER
BY 平均成绩 desc;
25、查询各科成绩前三名的记录:(不考虑成绩并列情况)
SELECT t1.S#
as 学生ID,t1.C#
as 课程ID,Score
as 分数
FROM SC t1
WHERE score
IN (SELECT
TOP
3 score
FROM SC
WHERE t1.C#= C#
ORDER
BY score
DESC
)
ORDER
BY t1.C#;
26、查询每门课程被选修的学生数
select c#,count(S#)
from sc
group by C#;
27、查询出只选修了一门课程的全部学生的学号和姓名
select SC.S#,Student.Sname,count(C#)
AS 选课数
from SC ,Student
where SC.S#=Student.S#
group
by SC.S# ,Student.Sname
having
count(C#)=1;
28、查询男生、女生人数
Select
count(Ssex)
as 男生人数 from Student
group
by Ssex having Ssex='男';
Select
count(Ssex)
as 女生人数 from Student
group
by Ssex having Ssex='女';
29、查询姓“张”的学生名单
SELECT Sname
FROM Student
WHERE Sname
like
'张%';
30、查询同名同性学生名单,并统计同名人数
select Sname,count(*)
from Student
group
by Sname having
count(*)>1;;
31、1981年出生的学生名单(注:Student表中Sage列的类型是datetime)
select Sname,
CONVERT(char (11),DATEPART(year,Sage))
as age
from student
where
CONVERT(char(11),DATEPART(year,Sage))='1981';
32、查询每门课程的平均成绩,结果按平均成绩升序排列,平均成绩相同时,按课程号降序排列
Select C#,Avg(score)
from SC
group by C#
order
by Avg(score),C#
DESC ;
33、查询平均成绩大于85的所有学生的学号、姓名和平均成绩
select Sname,SC.S# ,avg(score)
from Student,SC
where Student.S#=SC.S#
group
by SC.S#,Sname
having avg(score)>85;
34、查询课程名称为“数据库”,且分数低于60的学生姓名和分数
Select Sname,isnull(score,0)
from Student,SC,Course
where SC.S#=Student.S#
and SC.C#=Course.C#
and Course.Cname='数据库'and
score <60;
35、查询所有学生的选课情况;
SELECT SC.S#,SC.C#,Sname,Cname
FROM SC,Student,Course
where SC.S#=Student.S#
and SC.C#=Course.C# ;
36、查询任何一门课程成绩在70分以上的姓名、课程名称和分数;
SELECT
distinct student.S#,student.Sname,SC.C#,SC.score
FROM student,Sc
WHERE SC.score>=70
AND SC.S#=student.S#;
37、查询不及格的课程,并按课程号从大到小排列
select c#
from sc
where scor e
<60
order
by C# ;
38、查询课程编号为003且课程成绩在80分以上的学生的学号和姓名;
select SC.S#,Student.Sname
from SC,Student
where SC.S#=Student.S#
and Score>80
and C#='003';
39、求选了课程的学生人数
select
count(*)
from sc;
40、查询选修“叶平”老师所授课程的学生中,成绩最高的学生姓名及其成绩
select Student.Sname,score
from Student,SC,Course C,Teacher
where Student.S#=SC.S#
and SC.C#=C.C#
and C.T#=Teacher.T#
and Teacher.Tname='叶平'
and SC.score=(select
max(score)from SC
where C#=C.C# );
41、查询各个课程及相应的选修人数
select
count(*)
from sc
group by C#;
42、查询不同课程成绩相同的学生的学号、课程号、学生成绩
select
distinct A.S#,B.score
from SC A ,SC B
where A.Score=B.Score
and A.C#
<>B.C# ;
43、查询每门功成绩最好的前两名
SELECT t1.S#
as 学生ID,t1.C#
as 课程ID,Score
as 分数
FROM SC t1
WHERE score
IN (SELECT
TOP
2 score
FROM SC
WHERE t1.C#= C#
ORDER
BY score
DESC
)
ORDER
BY t1.C#;
44、统计每门课程的学生选修人数(超过10人的课程才统计)。要求输出课程号和选修人数,查询结果按人数降序排列,查询结果按人数降序排列,若人数相同,按课程号升序排列
select C#
as 课程号,count(*)
as 人数
from sc
group
by C#
order
by count(*)
desc,c#
45、检索至少选修两门课程的学生学号
select S#
from sc
group
by s#
having
count(*)
> =
2
46、查询全部学生都选修的课程的课程号和课程名
select C#,Cname
from Course
where C#
in (select c#
from sc
group by c#)
47、查询没学过“叶平”老师讲授的任一门课程的学生姓名
select Sname
from Student
where S#
not in (select S#
from Course,Teacher,SC
where Course.T#=Teacher.T#
and SC.C#=course.C#
and Tname='叶平');
48、查询两门以上不及格课程的同学的学号及其平均成绩
select S#,avg(isnull(score,0))
from SC
where S# in (select S#
from SC
where score
<60
group
by S# having
count(*)>2)group
by S#;
49、检索“004”课程分数小于60,按分数降序排列的同学学号
select S#
from SC
where C#='004'and
score <60
order
by score desc;
50、删除“002”同学的“001”课程的成绩
delete
from Sc where S#='001'and
C#='001';
转原文地址 http://topic.csdn.net/u/20081020/15/1abf54d0-f401-42ab-a75e-df90027ceba0.html
Course(C#,Cname,T#) 课程表
SC(S#,C#,score) 成绩表
Teacher(T#,Tname) 教师表
问题:
1、查询“001”课程比“002”课程成绩高的所有学生的学号;
select a.S#
from (select s#,score
from SC
where C#='001') a,(select
s#,score
from SC
where C#='002') b
where a.score>b.score
and a.s#=b.s#;
2、查询平均成绩大于60分的同学的学号和平均成绩;
select S#,avg(score)
from sc
group
by S# having
avg(score)
>60;
3、查询所有同学的学号、姓名、选课数、总成绩;
select Student.S#,Student.Sname,count(SC.C#),sum(score)
from Student
left
Outer join SC
on Student.S#=SC.S#
group
by Student.S#,Sname
4、查询姓“李”的老师的个数;
select
count(distinct(Tname))
from Teacher
where Tname
like
'李%';
新解:
select count(*) from Teacher where Tname like '李%' 或者 select count(*) from Teacher where left(Tname,1) = '李%'
5、查询没学过“叶平”老师课的同学的学号、姓名;
select Student.S#,Student.Sname
from Student
where S#
not
in (select
distinct( SC.S#)
from SC,Course,Teacher
where SC.C#=Course.C#
and Teacher.T#=Course.T#
and Teacher.Tname='叶平');
6、查询学过“001”并且也学过编号“002”课程的同学的学号、姓名;
select Student.S#,Student.Sname
from Student,SC
where Student.S#=SC.S#
and SC.C#='001'and
exists(
Select *
from SC
as SC_2 where SC_2.S#=SC.S#
and SC_2.C#='002');
7、查询学过“叶平”老师所教的所有课的同学的学号、姓名;
select S#,Sname
from Student
where S#
in (select S#
from SC ,Course ,Teacher
where SC.C#=Course.C#
and Teacher.T#=Course.T#
and Teacher.Tname='叶平'
group
by S# having
count(SC.C#)=(select
count(C#)
from Course,Teacher
where Teacher.T#=Course.T#
and Tname='叶平'));
8、查询课程编号“002”的成绩比课程编号“001”课程低的所有同学的学号、姓名;
Select S#,Sname
from (select Student.S#,Student.Sname,score ,(select
score from SC SC_2
where SC_2.S#=Student.S#
and SC_2.C#='002')
score2
from Student,SC
where Student.S#=SC.S#
and C#='001')
S_2 where score2
<score;
9、查询所有课程成绩小于60分的同学的学号、姓名;
select S#,Sname
from Student
where S#
not in (select Student.S#
from Student,SC
where S.S#=SC.S#
and score>60);
10、查询没有学全所有课的同学的学号、姓名;
select Student.S#,Student.Sname
from Student,SC
where Student.S#=SC.S#
group
by Student.S#,Student.Sname
having
count(C#) <(select
count(C#)
from Course);
11、查询至少有一门课与学号为“1001”的同学所学相同的同学的学号和姓名;
select S#,Sname
from Student,SC
where Student.S#=SC.S#
and C#
in select C#
from SC
where S#='1001';
12、查询至少学过学号为“001”同学所有一门课的其他同学学号和姓名;
select
distinct SC.S#,Sname
from Student,SC
where Student.S#=SC.S#
and C#
in (select C#
from SC
where S#='001');
13、把“SC”表中“叶平”老师教的课的成绩都更改为此课程的平均成绩;
update SC
set score=(select
avg(SC_2.score)
from SC SC_2
where SC_2.C#=SC.C# )
from Course,Teacher
where Course.C#=SC.C#
and Course.T#=Teacher.T#
and Teacher.Tname='叶平');
14、查询和“1002”号的同学学习的课程完全相同的其他同学学号和姓名;
select S#
from SC
where C# in (select C#
from SC
where S#='1002')
group
by S# having
count(*)=(select
count(*)
from SC
where S#='1002');
15、删除学习“叶平”老师课的SC表记录;
Delect SC
from course ,Teacher
where Course.C#=SC.C#
and Course.T#= Teacher.T#
and Tname='叶平';
16、向SC表中插入一些记录,这些记录要求符合以下条件:没有上过编号“003”课程的同学学号、2、
号课的平均成绩;
Insert SC
select S#,'002',(Select
avg(score)
from SC
where C#='002')
from Student
where S#
not in (Select S#
from SC
where C#='002');
17、按平均成绩从高到低显示所有学生的“数据库”、“企业管理”、“英语”三门的课程成绩,按如下形式显示: 学生ID,,数据库,企业管理,英语,有效课程数,有效平均分
SELECT S#
as 学生ID
,(SELECT score
FROM SC
WHERE SC.S#=t.S#
AND C#='004')
AS 数据库
,(SELECT score
FROM SC
WHERE SC.S#=t.S#
AND C#='001')
AS 企业管理
,(SELECT score
FROM SC
WHERE SC.S#=t.S#
AND C#='006')
AS 英语
,COUNT(*)
AS 有效课程数,
AVG(t.score)
AS 平均成绩
FROM SC
AS t
GROUP
BY S#
ORDER
BY avg(t.score)
18、查询各科成绩最高和最低的分:以如下形式显示:课程ID,最高分,最低分
SELECT L.C#
As 课程ID,L.score
AS 最高分,R.score
AS 最低分
FROM SC L ,SC
AS R
WHERE L.C#
= R.C#
and
L.score = (SELECT
MAX(IL.score)
FROM SC
AS IL,Student
AS IM
WHERE L.C#
= IL.C#
and IM.S#=IL.S#
GROUP
BY IL.C#)
AND
R.Score = (SELECT
MIN(IR.score)
FROM SC
AS IR
WHERE R.C#
= IR.C#
GROUP
BY IR.C#
);
19、按各科平均成绩从低到高和及格率的百分数从高到低顺序
SELECT t.C#
AS 课程号,max(course.Cname)AS 课程名,isnull(AVG(score),0)
AS 平均成绩
,100
* SUM(CASE
WHEN
isnull(score,0)>=60
THEN
1
ELSE
0
END)/COUNT(*)
AS 及格百分数
FROM SC T,Course
where t.C#=course.C#
GROUP
BY t.C#
ORDER
BY 100
* SUM(CASE
WHEN
isnull(score,0)>=60
THEN
1
ELSE
0
END)/COUNT(*)
DESC
20、查询如下课程平均成绩和及格率的百分数(用"1行"显示): 企业管理(001),马克思(002),OO&UML
(003),数据库(004)
SELECT
SUM(CASE
WHEN C#
='001'
THEN score
ELSE 0
END)/SUM(CASE
C# WHEN
'001'
THEN
1
ELSE
0
END)
AS 企业管理平均分
,100
* SUM(CASE
WHEN C#
= '001'
AND score
>= 60
THEN
1
ELSE
0
END)/SUM(CASE
WHEN C#
= '001'
THEN
1
ELSE
0
END)
AS 企业管理及格百分数
,SUM(CASE
WHEN C#
= '002'
THEN score
ELSE 0
END)/SUM(CASE
C# WHEN
'002'
THEN
1
ELSE
0
END)
AS 马克思平均分
,100
* SUM(CASE
WHEN C#
= '002'
AND score
>= 60
THEN
1
ELSE
0
END)/SUM(CASE
WHEN C#
= '002'
THEN
1
ELSE
0
END)
AS 马克思及格百分数
,SUM(CASE
WHEN C#
= '003'
THEN score
ELSE 0
END)/SUM(CASE
C# WHEN
'003'
THEN
1
ELSE
0
END)
AS UML平均分
,100
* SUM(CASE
WHEN C#
= '003'
AND score
>= 60
THEN
1
ELSE
0
END)/SUM(CASE
WHEN C#
= '003'
THEN
1
ELSE
0
END)
AS UML及格百分数
,SUM(CASE
WHEN C#
= '004'
THEN score
ELSE 0
END)/SUM(CASE
C# WHEN
'004'
THEN
1
ELSE
0
END)
AS 数据库平均分
,100
* SUM(CASE
WHEN C#
= '004'
AND score
>= 60
THEN
1
ELSE
0
END)/SUM(CASE
WHEN C#
= '004'
THEN
1
ELSE
0
END)
AS 数据库及格百分数
FROM SC
21、查询不同老师所教不同课程平均分从高到低显示
SELECT
max(Z.T#) AS 教师ID,MAX(Z.Tname)
AS 教师姓名,C.C#
AS 课程ID,MAX(C.Cname)
AS 课程名称,AVG(Score)
AS 平均成绩
FROM SC
AS T,Course
AS C ,Teacher
AS Z
where T.C#=C.C#
and C.T#=Z.T#
GROUP
BY C.C#
ORDER
BY AVG(Score)
DESC
22、查询如下课程成绩第
3 名到第
6 名的学生成绩单:企业管理(001),马克思(002),UML
(003),数据库(004)
[学生ID],[学生姓名],企业管理,马克思,UML,数据库,平均成绩
SELECT
DISTINCT
top 3
SC.S# As 学生学号,
Student.Sname AS 学生姓名 ,
T1.score AS 企业管理,
T2.score AS 马克思,
T3.score AS UML,
T4.score AS 数据库,
ISNULL(T1.score,0)
+ ISNULL(T2.score,0)
+ ISNULL(T3.score,0)
+ ISNULL(T4.score,0)
as 总分
FROM Student,SC
LEFT
JOIN SC AS T1
ON SC.S#
= T1.S#
AND T1.C# =
'001'
LEFT
JOIN SC
AS T2
ON SC.S#
= T2.S#
AND T2.C# =
'002'
LEFT
JOIN SC
AS T3
ON SC.S#
= T3.S#
AND T3.C# =
'003'
LEFT
JOIN SC
AS T4
ON SC.S#
= T4.S#
AND T4.C# =
'004'
WHERE student.S#=SC.S#
and
ISNULL(T1.score,0)
+ ISNULL(T2.score,0)
+ ISNULL(T3.score,0)
+ ISNULL(T4.score,0)
NOT
IN
(SELECT
DISTINCT
TOP
15
WITH TIES
ISNULL(T1.score,0)
+ ISNULL(T2.score,0)
+ ISNULL(T3.score,0)
+ ISNULL(T4.score,0)
FROM sc
LEFT
JOIN sc
AS T1
ON sc.S#
= T1.S#
AND T1.C# =
'k1'
LEFT
JOIN sc
AS T2
ON sc.S#
= T2.S#
AND T2.C# =
'k2'
LEFT
JOIN sc
AS T3
ON sc.S#
= T3.S#
AND T3.C# =
'k3'
LEFT
JOIN sc
AS T4
ON sc.S#
= T4.S#
AND T4.C# =
'k4'
ORDER
BY ISNULL(T1.score,0)
+ ISNULL(T2.score,0)
+ ISNULL(T3.score,0)
+ ISNULL(T4.score,0)
DESC);
23、统计列印各科成绩,各分数段人数:课程ID,课程名称,[100-85],[85-70],[70-60],[
<60]
SELECT SC.C#
as 课程ID, Cname
as 课程名称
,SUM(CASE
WHEN score
BETWEEN 85
AND
100
THEN
1
ELSE
0
END)
AS [100 - 85]
,SUM(CASE
WHEN score
BETWEEN 70
AND
85
THEN
1
ELSE
0
END)
AS [85 - 70]
,SUM(CASE
WHEN score
BETWEEN 60
AND
70
THEN
1
ELSE
0
END)
AS [70 - 60]
,SUM(CASE
WHEN score
< 60
THEN
1
ELSE
0
END)
AS [60 -]
FROM SC,Course
where SC.C#=Course.C#
GROUP
BY SC.C#,Cname;
24、查询学生平均成绩及其名次
SELECT
1+(SELECT
COUNT(
distinct 平均成绩)
FROM (SELECT S#,AVG(score)
AS 平均成绩
FROM SC
GROUP
BY S#
) AS T1
WHERE 平均成绩
> T2.平均成绩)
as 名次,
S# as 学生学号,平均成绩
FROM (SELECT S#,AVG(score) 平均成绩
FROM SC
GROUP
BY S#
) AS T2
ORDER
BY 平均成绩 desc;
25、查询各科成绩前三名的记录:(不考虑成绩并列情况)
SELECT t1.S#
as 学生ID,t1.C#
as 课程ID,Score
as 分数
FROM SC t1
WHERE score
IN (SELECT
TOP
3 score
FROM SC
WHERE t1.C#= C#
ORDER
BY score
DESC
)
ORDER
BY t1.C#;
26、查询每门课程被选修的学生数
select c#,count(S#)
from sc
group by C#;
27、查询出只选修了一门课程的全部学生的学号和姓名
select SC.S#,Student.Sname,count(C#)
AS 选课数
from SC ,Student
where SC.S#=Student.S#
group
by SC.S# ,Student.Sname
having
count(C#)=1;
28、查询男生、女生人数
Select
count(Ssex)
as 男生人数 from Student
group
by Ssex having Ssex='男';
Select
count(Ssex)
as 女生人数 from Student
group
by Ssex having Ssex='女';
29、查询姓“张”的学生名单
SELECT Sname
FROM Student
WHERE Sname
like
'张%';
30、查询同名同性学生名单,并统计同名人数
select Sname,count(*)
from Student
group
by Sname having
count(*)>1;;
31、1981年出生的学生名单(注:Student表中Sage列的类型是datetime)
select Sname,
CONVERT(char (11),DATEPART(year,Sage))
as age
from student
where
CONVERT(char(11),DATEPART(year,Sage))='1981';
32、查询每门课程的平均成绩,结果按平均成绩升序排列,平均成绩相同时,按课程号降序排列
Select C#,Avg(score)
from SC
group by C#
order
by Avg(score),C#
DESC ;
33、查询平均成绩大于85的所有学生的学号、姓名和平均成绩
select Sname,SC.S# ,avg(score)
from Student,SC
where Student.S#=SC.S#
group
by SC.S#,Sname
having avg(score)>85;
34、查询课程名称为“数据库”,且分数低于60的学生姓名和分数
Select Sname,isnull(score,0)
from Student,SC,Course
where SC.S#=Student.S#
and SC.C#=Course.C#
and Course.Cname='数据库'and
score <60;
35、查询所有学生的选课情况;
SELECT SC.S#,SC.C#,Sname,Cname
FROM SC,Student,Course
where SC.S#=Student.S#
and SC.C#=Course.C# ;
36、查询任何一门课程成绩在70分以上的姓名、课程名称和分数;
SELECT
distinct student.S#,student.Sname,SC.C#,SC.score
FROM student,Sc
WHERE SC.score>=70
AND SC.S#=student.S#;
37、查询不及格的课程,并按课程号从大到小排列
select c#
from sc
where scor e
<60
order
by C# ;
38、查询课程编号为003且课程成绩在80分以上的学生的学号和姓名;
select SC.S#,Student.Sname
from SC,Student
where SC.S#=Student.S#
and Score>80
and C#='003';
39、求选了课程的学生人数
select
count(*)
from sc;
40、查询选修“叶平”老师所授课程的学生中,成绩最高的学生姓名及其成绩
select Student.Sname,score
from Student,SC,Course C,Teacher
where Student.S#=SC.S#
and SC.C#=C.C#
and C.T#=Teacher.T#
and Teacher.Tname='叶平'
and SC.score=(select
max(score)from SC
where C#=C.C# );
41、查询各个课程及相应的选修人数
select
count(*)
from sc
group by C#;
42、查询不同课程成绩相同的学生的学号、课程号、学生成绩
select
distinct A.S#,B.score
from SC A ,SC B
where A.Score=B.Score
and A.C#
<>B.C# ;
43、查询每门功成绩最好的前两名
SELECT t1.S#
as 学生ID,t1.C#
as 课程ID,Score
as 分数
FROM SC t1
WHERE score
IN (SELECT
TOP
2 score
FROM SC
WHERE t1.C#= C#
ORDER
BY score
DESC
)
ORDER
BY t1.C#;
44、统计每门课程的学生选修人数(超过10人的课程才统计)。要求输出课程号和选修人数,查询结果按人数降序排列,查询结果按人数降序排列,若人数相同,按课程号升序排列
select C#
as 课程号,count(*)
as 人数
from sc
group
by C#
order
by count(*)
desc,c#
45、检索至少选修两门课程的学生学号
select S#
from sc
group
by s#
having
count(*)
> =
2
46、查询全部学生都选修的课程的课程号和课程名
select C#,Cname
from Course
where C#
in (select c#
from sc
group by c#)
47、查询没学过“叶平”老师讲授的任一门课程的学生姓名
select Sname
from Student
where S#
not in (select S#
from Course,Teacher,SC
where Course.T#=Teacher.T#
and SC.C#=course.C#
and Tname='叶平');
48、查询两门以上不及格课程的同学的学号及其平均成绩
select S#,avg(isnull(score,0))
from SC
where S# in (select S#
from SC
where score
<60
group
by S# having
count(*)>2)group
by S#;
49、检索“004”课程分数小于60,按分数降序排列的同学学号
select S#
from SC
where C#='004'and
score <60
order
by score desc;
50、删除“002”同学的“001”课程的成绩
delete
from Sc where S#='001'and
C#='001';
转原文地址 http://topic.csdn.net/u/20081020/15/1abf54d0-f401-42ab-a75e-df90027ceba0.html