zoj 2476
2009-10-03 10:28
267 查看
Total Amount
Time Limit: 1 Second Memory Limit: 32768 KB
Given a list of monetary amounts in a standard format, please calculate the total amount.
We define the format as follows:
1. The amount starts with '$'.
2. The amount could have a leading '0' if and only if it is less then 1.
3. The amount ends with a decimal point and exactly 2 following digits.
4. The digits to the left of the decimal point are separated into groups of three by commas (a group of one or two digits may appear on the left).
Input
The input consists of multiple tests. The first line of each test contains an integer N (1 <= N <= 10000) which indicates the number of amounts. The next N lines contain N amounts. All amounts and the total amount are between $0.00 and $20,000,000.00, inclusive. N=0 denotes the end of input.
Output
For each input test, output the total amount.
Sample Input
2
$1,234,567.89
$9,876,543.21
3
$0.01
$0.10
$1.00
0
Sample Output
$11,111,111.10
$1.11
//2476
#include <iostream>
#include <string>
using namespace std;
int main()
{
int n ;
while(cin>>n&&n!=0)
{
string str;
n--;
cin>>str;
string sum = str;
sum = sum.substr(1,sum.length());
while(n--)
{
cin>>str;
str = str.substr(1,str.length());
if(sum.length()<str.length())
swap(sum,str);
int f = 0;
int i , j;
for(i = sum.length()-1, j = str.length()-1 ; j>=0 ; i--,j--)
{
if(str.at(j)!='.'&&str.at(j)!=',')
{
int t = sum.at(i) + str.at(j) + f - '0'*2;
char tt;
if( t>=10)
{
f = 1;
tt = char(t%10+'0');
}
else
{
f = 0;
tt = char(t+'0');
}
sum[i] = tt;
}
}
while(f!=0&&i>=0)
{
if(sum.at(i)!='.'&&sum.at(i)!=',')
{
int t = sum.at(i) + f - '0';
char tt;
if( t>=10)
{
f = 1;
tt = char(t%10+'0');
}
else
{
f = 0;
tt = char(t+'0');
}
sum[i] = tt;
}
i--;
}
if(f!=0&&i==-1)
sum = char(f+'0') + sum;
}
sum = '$' + sum;
cout<<sum<<endl;
}
return 0;
}
================================================
测试数据
2
$9,099,802.11
$23,234,999,999,999,001.23
2
$998.09
$1.00
2
$1.00
$1.00
3
$0.22
$39,178,437,598,718,923.78
$485,983,720.00
2
$999.00
$1.00
2
$872.00
$23.01
2
$0.01
$0.99
2
$0.01
$999.99
10
$999,234,999,999,999,001.23
$999,234,999,999,999,001.23
$999,234,999,999,999,001.23
$999,234,999,999,999,001.23
$999,234,999,999,999,001.23
$999,234,999,999,999,001.23
$999,234,999,999,999,001.23
$999,234,999,999,999,001.23
$999,234,999,999,999,001.23
$999,234,999,999,999,001.23
Time Limit: 1 Second Memory Limit: 32768 KB
Given a list of monetary amounts in a standard format, please calculate the total amount.
We define the format as follows:
1. The amount starts with '$'.
2. The amount could have a leading '0' if and only if it is less then 1.
3. The amount ends with a decimal point and exactly 2 following digits.
4. The digits to the left of the decimal point are separated into groups of three by commas (a group of one or two digits may appear on the left).
Input
The input consists of multiple tests. The first line of each test contains an integer N (1 <= N <= 10000) which indicates the number of amounts. The next N lines contain N amounts. All amounts and the total amount are between $0.00 and $20,000,000.00, inclusive. N=0 denotes the end of input.
Output
For each input test, output the total amount.
Sample Input
2
$1,234,567.89
$9,876,543.21
3
$0.01
$0.10
$1.00
0
Sample Output
$11,111,111.10
$1.11
//2476
#include <iostream>
#include <string>
using namespace std;
int main()
{
int n ;
while(cin>>n&&n!=0)
{
string str;
n--;
cin>>str;
string sum = str;
sum = sum.substr(1,sum.length());
while(n--)
{
cin>>str;
str = str.substr(1,str.length());
if(sum.length()<str.length())
swap(sum,str);
int f = 0;
int i , j;
for(i = sum.length()-1, j = str.length()-1 ; j>=0 ; i--,j--)
{
if(str.at(j)!='.'&&str.at(j)!=',')
{
int t = sum.at(i) + str.at(j) + f - '0'*2;
char tt;
if( t>=10)
{
f = 1;
tt = char(t%10+'0');
}
else
{
f = 0;
tt = char(t+'0');
}
sum[i] = tt;
}
}
while(f!=0&&i>=0)
{
if(sum.at(i)!='.'&&sum.at(i)!=',')
{
int t = sum.at(i) + f - '0';
char tt;
if( t>=10)
{
f = 1;
tt = char(t%10+'0');
}
else
{
f = 0;
tt = char(t+'0');
}
sum[i] = tt;
}
i--;
}
if(f!=0&&i==-1)
sum = char(f+'0') + sum;
}
sum = '$' + sum;
cout<<sum<<endl;
}
return 0;
}
================================================
测试数据
2
$9,099,802.11
$23,234,999,999,999,001.23
2
$998.09
$1.00
2
$1.00
$1.00
3
$0.22
$39,178,437,598,718,923.78
$485,983,720.00
2
$999.00
$1.00
2
$872.00
$23.01
2
$0.01
$0.99
2
$0.01
$999.99
10
$999,234,999,999,999,001.23
$999,234,999,999,999,001.23
$999,234,999,999,999,001.23
$999,234,999,999,999,001.23
$999,234,999,999,999,001.23
$999,234,999,999,999,001.23
$999,234,999,999,999,001.23
$999,234,999,999,999,001.23
$999,234,999,999,999,001.23
$999,234,999,999,999,001.23
相关文章推荐
- zoj 2476 Total Amount(水~)
- 【求助】zoj 2476求和水题
- ZOJ 2476 Total Amount
- zoj 2476 Total Amount
- zoj 2476 Total Amount
- Total Amount zoj 2476
- zoj 2476 Total Amount
- zoj 2476 Total Amount(模拟题,细节处理特别多)
- zoj_2476 Total Amount
- zoj 2476 Total Amount
- ZOJ 2476 Total Amount 字符串
- ZOJ Problem Set - 2476 Total Amount
- B-Total Amount (ZOJ 2476)
- ZOJ 2476 Total Amount 字符串
- ZOJ-2476
- zoj 2476 Total Amount
- ZOJ 2476 Total Amount
- ZOJ 2476 Total Amount (字符串处理)
- ZOJ 2476 Total Amount
- zoj 1610 Count the Colors