您的位置：首页 > 编程语言 > Java开发

Struts2中拦截器与过滤器的执行顺序

2009-08-23 16:18 465 查看

通过上图可以看到，顺序应该是我们配的filter在前，之后是struts2的FilterDispatcher，然后是各个拦截器，最后原路返回。

下面我们来验证一下：

web.xml

<?xml version="1.0" encoding="UTF-8"?>

<web-app version="2.4"

xmlns="http://java.sun.com/xml/ns/j2ee"

xmlns:xsi="http://www.w3.org/2001/XMLSchema-instance"

xsi:schemaLocation="http://java.sun.com/xml/ns/j2ee

http://java.sun.com/xml/ns/j2ee/web-app_2_4.xsd">

<welcome-file-list>

<welcome-file>login.jsp</welcome-file>

</welcome-file-list>

<filter>

<filter-name>MyFilter</filter-name>

<filter-class>filter.MyFilter</filter-class>

</filter>

<filter-mapping>

<filter-name>MyFilter</filter-name>

<url-pattern>/*</url-pattern>

</filter-mapping>

<filter>

<filter-name>struts2</filter-name>

<filter-class>org.apache.struts2.dispatcher.FilterDispatcher</filter-class>

</filter>

<filter-mapping>

<filter-name>struts2</filter-name>

<url-pattern>/*</url-pattern>

</filter-mapping>

</web-app>

struts.xml

<!DOCTYPE struts PUBLIC

"-//Apache Software Foundation//DTD Struts Configuration 2.0//EN"

"http://struts.apache.org/dtds/struts-2.0.dtd">

<struts>

<package name="default" extends="struts-default">

<interceptors>

<interceptor name="loginInterceptor" class="interceptor.LoginInterceptor" />

<interceptor-stack name="loginStack">

<interceptor-ref name="loginInterceptor" />

<interceptor-ref name="defaultStack" />

</interceptor-stack>

</interceptors>

<default-interceptor-ref name="loginStack"></default-interceptor-ref>

<global-results>

<result name="login">/login.jsp</result>

</global-results>

<action name="Login" class="action.LoginAction">

<result>/index.jsp</result>

</action>

</package>

</struts>

login.jsp

<%@ page language="java" import="java.util.*" pageEncoding="ISO-8859-1"%>

<!DOCTYPE HTML PUBLIC "-//W3C//DTD HTML 4.01 Transitional//EN">

<html>

<head>

<title>My JSP 'index.jsp' starting page</title>

</head>

<body>

<h3>Login</h3>

<hr>

<form action="Login.action" method="POST">

Name: <input type="text" name="username" />

<input type="submit" value="submit" />

</form>

</body>

</html>

index.jsp

<%@ page language="java" import="java.util.*" pageEncoding="ISO-8859-1"%>

<!DOCTYPE HTML PUBLIC "-//W3C//DTD HTML 4.01 Transitional//EN">

<html>

<head>

<title>My JSP 'index.jsp' starting page</title>

</head>

<body>

<h3>Login Success!</h3>

</body>

</html>

filter.MyFilter

package filter;

import java.io.IOException;

import javax.servlet.Filter;

import javax.servlet.FilterChain;

import javax.servlet.FilterConfig;

import javax.servlet.ServletException;

import javax.servlet.ServletRequest;

import javax.servlet.ServletResponse;

public class MyFilter implements Filter {

public void destroy() {

}

public void doFilter(ServletRequest request, ServletResponse response,

FilterChain chain) throws IOException, ServletException {

System.out.println("请求过滤");

chain.doFilter(request, response);

System.out.println("返回过滤");

}

public void init(FilterConfig arg0) throws ServletException {

}

}

interceptor.LoginInterceptor

package interceptor;

import org.apache.struts2.ServletActionContext;

import com.opensymphony.xwork2.ActionInvocation;

import com.opensymphony.xwork2.interceptor.AbstractInterceptor;

public class LoginInterceptor extends AbstractInterceptor {

private static final long serialVersionUID = -2796326480994355318L;

@Override

public String intercept(ActionInvocation ai) throws Exception {

System.out.println("请求拦截");

if(!"YOYO".equals(ServletActionContext.getRequest().getParameter("username"))){

return "login";

}

String result = ai.invoke();

System.out.println("返回拦截");

return result;

}

}

action.LoginAction

package action;

public class LoginAction {

public String execute(){

System.out.println("登陆ACTION");

return "success";

}

}

部署好后打开login.jsp，输入任意非"YOYO"字符，控制台打印出

请求过滤

请求拦截

返回过滤

说明拦截之后还会按照原路返回；

如果输入"YOYO"，则打印出

请求过滤

请求拦截

登陆ACTION

返回拦截

返回过滤

由此可以验证它的执行顺序 = =。

内容来自用户分享和网络整理，不保证内容的准确性，如有侵权内容，可联系管理员处理

标签：

相关文章推荐

新的分享

章节导航