转载：在ASP.net 3.5中 用JSON序列化对象（两种方法）

asp.net3.5中已经集成了序列化对象为json的方法。

1:System.Runtime.Serialization.Json;
2:System.Web.Script.Serialization两个命名空间下的不同方法进行序列化和反序列化。

第一种方法：System.Runtime.Serialization.Json

public class JsonHelper
{
/// <summary>
/// 生成Json格式
/// </summary>
/// <typeparam name="T"></typeparam>
/// <param name="obj"></param>
/// <returns></returns>
public static string GetJson<T>(T obj)
{
DataContractJsonSerializer json = new DataContractJsonSerializer(obj.GetType());
using (MemoryStream stream = new MemoryStream())
{
json.WriteObject(stream, obj);
string szJson = Encoding.UTF8.GetString(stream.ToArray()); return szJson;
}
}
/// <summary>
/// 获取Json的Model
/// </summary>
/// <typeparam name="T"></typeparam>
/// <param name="szJson"></param>
/// <returns></returns>
public static T ParseFromJson<T>(string szJson)
{
T obj = Activator.CreateInstance<T>();
using (MemoryStream ms = new MemoryStream(Encoding.UTF8.GetBytes(szJson)))
{
DataContractJsonSerializer serializer = new DataContractJsonSerializer(obj.GetType());
return (T)serializer.ReadObject(ms);
}
}
}
public class topMenu
{
public string id { get; set; }
public string title { get; set; }
public string defaulturl { get; set; }
}
topMenu t_menu = new topMenu()
{
id = "1",
title = "全局",
defaulturl = "123456"
};
List<topMenu> l_topmenu = new List<topMenu>();
for (int i = 0; i < 3; i++)
{
l_topmenu.Add(t_menu);
}
Response.Write(JsonHelper.GetJson<List<topMenu>>(l_topmenu));

输出结果为：
[{"defaulturl":"123456","id":"1","title":"全局"},{"defaulturl":"123456","id":"1","title":"全局"},{"defaulturl":"123456","id":"1","title":"全局"}]

下面利用上面ParseFromJson方法读取Json
输出结果为：全局

string szJson = @"{""id"":""1"",""title"":""全局"",""defaulturl"":""123456""} ";
topMenu t_menu2 = JsonHelper.ParseFromJson<topMenu>(szJson);
Response.Write(t_menu2.title);

第二种方法:System.Web.Script.Serialization(引用System.Web.Extensions.dll)还是用到上面方法中JSON属性的类,序列化方式不一样。

topMenu t_menu = new topMenu()
{
id = "1",
title = "全局",
defaulturl = "123456"
};

List<topMenu> l_topmenu = new List<topMenu>();

for (int i = 0; i < 3; i++)
{
l_topmenu.Add(t_menu);
}

下面用这种方式输出：

JavaScriptSerializer jss = new JavaScriptSerializer();
Response.Write( jss.Serialize(l_topmenu ));

输出结果是相同的

[{"defaulturl":"123456","id":"1","title":"全局"},{"defaulturl":"123456","id":"1","title":"全局"},{"defaulturl":"123456","id":"1","title":"全局"}]

JavaScriptSerializer中的Deserialize方法读取Json

string szJson = @"{""id"":""1"",""title"":""全局"",""defaulturl"":""123456""} ";
topMenu toptabmenu = jss.Deserialize<topMenu>(szJson);
Response.Write( jss.Serialize(toptabmenu.title));

输出结果为：全局

综上:两种方法个有好处。一个比较灵活。[ScriptIgnore] ,可以让JSON序列化忽略它从而不输出。不被序列化。