学java的认识从java词汇开始
2009-08-15 22:05
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员工业绩表:inwork +----+------------+----------+------------+ | id sname smoney sprovice +----+------------+----------+------------+ | 1 zhangsan 2098 A +----+------------+----------+------------+ | 2 lishi 3000 B +----+------------+----------+------------+ | 3 wangwu 6789 C +----+------------+----------+------------+ | 4 liumazi 4587 C +----+------------+----------+------------+ | 5 dongjiu 3298 B +----+------------+----------+------------+ | 6 shiga 4567 A +----+------------+----------+------------+ | 7 heiqi 4007 A +----+------------+----------+------------+ | 8 diuba 3500 B +----+------------+----------+------------+ | 9 behkanm 2900 C +----+------------+----------+------------+ SQL: +-------------------------------------------------------+ CREATE TABLE IF NOT EXISTS `inwork` ( `id` int(11) NOT NULL auto_increment, `sname` varchar(20) default NULL, `smoney` int(11) default NULL, `sprovice` varchar(12) default NULL, PRIMARY KEY (`id`) ) ENGINE=MyISAM DEFAULT CHARSET=utf8 AUTO_INCREMENT=7 ; INSERT INTO `inwork` VALUES (1, 'zhangsan', 2098, 'A'); INSERT INTO `inwork` VALUES (2, 'lishi', 3000, 'B'); INSERT INTO `inwork` VALUES (3, 'wangwu', 6789, 'C'); INSERT INTO `inwork` VALUES (4, 'liumazi', 4587, 'C'); INSERT INTO `inwork` VALUES (5, 'dongjiu', 3298, 'B'); INSERT INTO `inwork` VALUES (6, 'shiga', 4567, 'A'); INSERT INTO `inwork` VALUES (7, 'heiqi', 4007, 'A'); INSERT INTO `inwork` VALUES (8, 'diuba', 3500, 'B'); INSERT INTO `inwork` VALUES (9, 'behkanm', 2900, 'C'); +-------------------------------------------------------+ 要求: 1.显示出业绩大于同一地区业绩值最大的合同id ,姓名,地区,业绩 +-------------------------------------------+ |SELECT a.id, a.sname, a.smoney, a.sprovice | |FROM inwork a, ( | | SELECT max( smoney ) AS maxmoney, sprovice| | FROM inwork | | GROUP BY sprovice | |)b | |WHERE a.smoney = b.maxmoney | |AND a.sprovice = b.sprovice | +-------------------------------------------+ 2.显示出业绩大于同一地区平均值的合同id ,姓名,地区,业绩 +-------------------------------------------+ |SELECT a.id, a.sname, a.smoney, a.sprovice | |FROM inwork a, ( | | SELECT avg( smoney ) AS avgmoney, sprovice| | FROM inwork | | GROUP BY sprovice | |)b | |WHERE a.smoney > b.avgmoney | |AND a.sprovice = b.sprovice | +-------------------------------------------+ 3.把同一地区的平均业绩,地区插入到新表中(新表只包含两个字段即:平均业绩和地区) +-------------------------------------------+ |create table t1 as( | | select avg(smoney) AS avgmoneys, sprovice | | from inwork | | group by sprovice) ; | +-------------------------------------------+
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