目前90%的病毒不再自我复制
2009-06-05 11:01
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Kaspersky Lab的高级反病毒研究员Roel Schouwenberg近日在谈到过去5年malware的变化时表示:
1、目前90%的病毒不再自我复制。
Criminals generally don't want to draw any attention from anti-malware companies and/or law enforcement. What also adds to this is that today about 90% of the malware we see is not self-replicating.
2、malware数量迅速增长,2007年是前20年之和,2008年是2007年的10倍,目前每天发现的新威胁达4万种。
In 2008 we saw ten times as much malware as in 2007. In 2007 we saw the same amount of malware as in the whole twenty years before that combined. Right now we see up to 40,000 new threats per day, even two years ago that would have been very hard to imagine.
3.写malware者向盈利性目的转变
There has also been a shift in how people are writing malware. In 2004 we were already seeing the change from people writing malware for fun to writing malware for profit. These days over 98% of all the malware we see is created with profit in mind. So we're fighting professional cyber criminals rather than teenage kids trying to prove themselves like five years ago. http://www.net-security.org/article.php?id=1219&p=1
1、目前90%的病毒不再自我复制。
Criminals generally don't want to draw any attention from anti-malware companies and/or law enforcement. What also adds to this is that today about 90% of the malware we see is not self-replicating.
2、malware数量迅速增长,2007年是前20年之和,2008年是2007年的10倍,目前每天发现的新威胁达4万种。
In 2008 we saw ten times as much malware as in 2007. In 2007 we saw the same amount of malware as in the whole twenty years before that combined. Right now we see up to 40,000 new threats per day, even two years ago that would have been very hard to imagine.
3.写malware者向盈利性目的转变
There has also been a shift in how people are writing malware. In 2004 we were already seeing the change from people writing malware for fun to writing malware for profit. These days over 98% of all the malware we see is created with profit in mind. So we're fighting professional cyber criminals rather than teenage kids trying to prove themselves like five years ago. http://www.net-security.org/article.php?id=1219&p=1
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