实现页面加载效果
2009-06-03 11:20
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先看看效果:
Code
using System;
using System.Data;
using System.Configuration;
using System.Collections;
using System.Web;
using System.Web.Security;
using System.Web.UI;
using System.Web.UI.WebControls;
using System.Web.UI.WebControls.WebParts;
using System.Web.UI.HtmlControls;
using System.Threading;
public partial class _Default : System.Web.UI.Page
{
protected void Page_Load(object sender, EventArgs e)
{
if (!Page.IsPostBack)
{
this.Timer1.Enabled = true;
}
}
protected void Timer1_Tick(object sender, EventArgs e)
{
Thread.Sleep(3000);
DataTable dt = new DataTable();
DataColumn dcname = new DataColumn("name");
DataColumn dcage = new DataColumn("age");
dt.Columns.Add(dcname);
dt.Columns.Add(dcage);
dt.Rows.Add(new object[]{"engine","25"});
dt.Rows.Add(new object[] { "Water", "30" });
GridView1.DataSource = dt;
GridView1.DataBind();
this.Timer1.Enabled = false;
}
}
Code
using System;
using System.Data;
using System.Configuration;
using System.Collections;
using System.Web;
using System.Web.Security;
using System.Web.UI;
using System.Web.UI.WebControls;
using System.Web.UI.WebControls.WebParts;
using System.Web.UI.HtmlControls;
using System.Threading;
public partial class _Default : System.Web.UI.Page
{
protected void Page_Load(object sender, EventArgs e)
{
if (!Page.IsPostBack)
{
this.Timer1.Enabled = true;
}
}
protected void Timer1_Tick(object sender, EventArgs e)
{
Thread.Sleep(3000);
DataTable dt = new DataTable();
DataColumn dcname = new DataColumn("name");
DataColumn dcage = new DataColumn("age");
dt.Columns.Add(dcname);
dt.Columns.Add(dcage);
dt.Rows.Add(new object[]{"engine","25"});
dt.Rows.Add(new object[] { "Water", "30" });
GridView1.DataSource = dt;
GridView1.DataBind();
this.Timer1.Enabled = false;
}
}
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