pku 3356 AGTC

#include <iostream>
#include <string>
using namespace std;
int v[1001][1001];
int main()
{
int m, n;
string s1, s2;
while(scanf("%d", &m)!=EOF)
{
cin >> s1;
scanf("%d", &n);
cin >> s2;

for(int i = 1; i <= n; ++i)
v[0][i] = i;
for(int i = 1; i <= m; ++i)
v[i][0] = i;

for(int i = 1; i <= m; ++i)
for(int j = 1; j <= n; ++j)
if(s1[i-1] == s2[j-1])
v[i][j] = min(min(v[i-1][j-1], v[i-1][j]+1), v[i][j-1]+1);
else
v[i][j] = min(min(v[i-1][j-1]+1, v[i-1][j]+1), v[i][j-1]+1);

printf("%d/n", v[m]
);
}
return 0;
}
/*				min{v[i-1][j-1], v[i-1][j]+1, v[i][j-1]+1}		(s[i] = s[j])
v[i][j] =
min{v[i-1][j-1]+1, v[i-1][j]+1, v[i][j-1]+1}	(s[i] != s[j])

//1.s[i] = s[j],其中v[i-1][j-1]+1表示不作处理,v[i-1][j]+1表示删除字符s[i],
v[i][j-1]+1表示在s[i]后添加s[j]

//s[i] != s[j],其中v[i-1][j-1]+1表示把s[i]变成s[j],v[i-1][j]+1表示删除字符s[i],
v[i][j-1]+1表示在s[i]后添加s[j]

//2.注意初始化的处理

result:
Problem: 3356  User: xiaofengsheng
Memory: 4288K  Time: 32MS
Language: G++  Result: Accepted

*/