LinqToXml

1.创建Xml树

<person id="1">
<name>Gaby</name>
<age>12</age>
<address>GuangZhou</address>
</person>
<person id="2">
<name>Bill</name>
<age>33</age>
<address>USA</address>
</person>
<person id="3">
<name>BiLy</name>
<age>19</age>
<address>HuNan</address>
</person>

如果要创建如上的XML树：

代码示例：

XElement xmlTree = new XElement("Root",

new XElement("person", new XElement("name", "Gaby"),

new XElement("age",18),

new XElement("address","GuangZhou")),

new XElement("person", new XElement("name", "Lily"),

new XElement("age",20),

new XElement("address","USA")),

new XElement("person", new XElement("name", "Bill"),

new XElement("age",55),

new XElement("address","English"))

);

foreach (var item in xmlTree.Elements())

{

Console.WriteLine(item);

}

输出结果：



2.读取XML文件
有以下XML文件：path:D:\NetDemo\LinqToXml\LinqToXml\XMLFile.xml

<?xml version="1.0" encoding="utf-8" ?>

<persons>

<person id="1">

<name>Gaby</name>

<age>16</age>

<address>GuangZhou</address>

</person>

<person id="2">

<name>Bill</name>

<age>33</age>

<address>USA</address>

</person>

<person id="3">

<name>BiLy</name>

<age>19</age>

<address>HuNan</address>

</person>

<person id="4">

<name>James</name>

<age>16</age>

<address>English</address>

</person>

</persons>

读取方法一：
XElement xml = XElement.Load(@"D:"NetDemo"LinqToXml"LinqToXml"XMLFile.xml");
Console.WriteLine("读取XML...");
foreach (var item in xml.Elements("person"))
{
Console.WriteLine(item.Element("name").Value+""t"
+item.Element("age").Value+""t"
+item.Element("address").Value);
}

读取方法二:（查询表达式）
var persons = from p in xml.Elements("person")
select new
{
Name = p.Element("name").Value,
Age = p.Element("age").Value,
Address = p.Element("address").Value

};

Console.WriteLine("读取XML...");

foreach (var item in persons)
{
Console.WriteLine(item.Name+"\t"+item.Age+"\t"+item.Address);
}

读取方法三：（lambada表达式）
var persons = xml.Elements("person").Select(p => new{

Id=p.Attribute("id").Value, //读取属性
Name = p.Element("name").Value,
Age = p.Element("age").Value,
Address = p.Element("address").Value
}
);

foreach (var item in persons)
{
Console.WriteLine(item.Name + ""t" + item.Age + ""t" + item.Address);
}

输出结果（相同）：