Euler Project Problem 6

The sum of the squares of the first ten natural numbers is,

1

2

+ 2

2

+ ... + 10

2

= 385
The square of the sum of the first ten natural numbers is,

(1 + 2 + ... + 10)

2

= 55

2

= 3025
Hence the difference between the sum of the squares of the first ten natural numbers and the square of the sum is 3025

385 = 2640.

Find the difference between the sum of the squares of the first one hundred natural numbers and the square of the sum.

code:

dif = 0
for i in range(1,101):
for j in range (i+1,101):
dif += 2*i*j
print dif