Java面试题：有数组a[n]，用java代码将数组元素顺序颠倒

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/**

* 颠倒数组数据的先后顺序

*

* @author 老紫竹 java2000.net

*/

public class Test {

public static void reverse(int[] a, int left, int right) {

if (left >= right)

return;

int temp;

temp = a[left];

a[left] = a[right];

a[right] = temp;

reverse(a, ++left, --right);

}

public static void main(String args[]) {

int[] a = { 1, 2, 3, 4, 5 };

reverse(a, 0, a.length - 1);

for (int i = 0; i < a.length; i++)

System.out.println(a[i]);

}

}

/**
* 颠倒数组数据的先后顺序
*
* @author 老紫竹 java2000.net
*/
public class Test {
public static void reverse(int[] a, int left, int right) {
if (left >= right)
return;
int temp;
temp = a[left];
a[left] = a[right];
a[right] = temp;
reverse(a, ++left, --right);
}

public static void main(String args[]) {
int[] a = { 1, 2, 3, 4, 5 };
reverse(a, 0, a.length - 1);
for (int i = 0; i < a.length; i++)
System.out.println(a[i]);
}
}

从字符串的两端开始交换，然后缩短字符串的长度，从新的两端开始。