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apache的httpclient报出的java.lang.IllegalArgumentException: Invalid uri ...... escaped absolute path not valid

2008-12-22 14:15 751 查看
今天用httpclient创建get请求时,总是报:java.lang.IllegalArgumentException: Invalid uri 'http://192.168.100.51/xcap-root/resource-lists/users/sip:alice@192.168.100.30/index/~~/resource-lists/list[@name="friends"]/entry[1]/display-name': escaped absolute path not valid
原因很简单,就是因为有[,],"这样的字符。忙乎了半天,终于搞定,其实很简单,用到java.net.URLEncoder原来写的代码:String s = "http://" + ip + "/xcap-root/resource-lists/users/sip:alice@192.168.100.30/index/~~/resource-lists/list[@name=/"friends/"]/entry[1]/display-name";

现在改为:String s = "http://" + ip + "/xcap-root/resource-lists/users/sip:alice@192.168.100.30/index/~~/resource-lists/list"+URLEncoder.encode("[", "utf-8")+"@name="+URLEncoder.encode("/"", "utf-8")+"friends"+URLEncoder.encode("/"", "utf-8")+URLEncoder.encode("]", "utf-8")+"/entry"+URLEncoder.encode("[", "utf-8")+"1"+URLEncoder.encode("]", "utf-8")+"/display-name";
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标签:  path apache string
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