hibernate: could not get next sequence value
2008-07-20 21:57
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hibernate配置oracle自增序列时指定方案，否则报错：org.hibernate.exception.SQLGrammarException: could not get next sequence value
即使用该序列所属的用户也不行。
<id name="id" type="java.lang.Long">
<column name="ID" precision="22" scale="0" />
<generator class="sequence">
<param name="sequence">ADMIN.SEQ_LEVEL1_ID</param>
</generator>
</id>
即使用该序列所属的用户也不行。
<id name="id" type="java.lang.Long">
<column name="ID" precision="22" scale="0" />
<generator class="sequence">
<param name="sequence">ADMIN.SEQ_LEVEL1_ID</param>
</generator>
</id>
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