根据时间段，返回时间段的工作小时数

/* 根据时间段，返回时间段的工作小时数：一天按8小时 */

CREATE FUNCTION [dbo].[fc_GetWorkHour] (@startdate smalldatetime,@enddate smalldatetime)

RETURNS int AS

BEGIN

declare @delayday int --暂用工时(日)

if(@startdate is null)

return 0

if(@enddate is null)

return 0

declare @tmptb table(dt smalldatetime)

declare @WeekendNum int

declare @s smalldatetime

set @s=@startdate

while @s<=convert(varchar(4),year(@enddate))+'-'+convert(varchar(2),month(@enddate))+'-'+convert(varchar(2),day(@enddate))+' 23:59'

begin

insert into @tmptb select @s set @s=dateadd(day,1,@s)

end --时间段内工作日个数

select @WeekendNum=count(*) from @tmptb where datepart(weekday,dt) not in (1,7)--工作个数（星期日为1,星期一为2,星期二为3....）

--开头，结尾是否是工作日，如果是的话，就除去

if(datepart(dw,@startdate)>1 and datepart(dw,@startdate)<7)

begin

set @WeekendNum=@WeekendNum-1

end

if(datepart(dw,@enddate)>1 and datepart(dw,@enddate)<7)

begin

set @WeekendNum=@WeekendNum-1

end

--计算整工作日小时数

set @delayday= 8*@WeekendNum*60

if(@delayday<0)

begin

set @delayday=0

end

if( datediff(dd,@startdate,@enddate)=0)--开始结束同一天

begin

set @delayday=datediff(mi,@startdate,@enddate)

end

else

begin

if(datepart(dw,@startdate)>1 and datepart(dw,@startdate)<7)

begin

if(datediff(mi,@startdate,convert(varchar(4),year(@startdate))+'-'+convert(varchar(2),month(@startdate))+'-'+convert(varchar(2),day(@startdate))+' 17:30')>0)

begin

set @delayday=@delayday+datediff(mi,@startdate,convert(varchar(4),year(@startdate))+'-'+convert(varchar(2),month(@startdate))+'-'+convert(varchar(2),day(@startdate))+' 17:30')

end

end

if(datepart(dw,@enddate)>1 and datepart(dw,@enddate)<7)

begin

if(datediff(mi,convert(varchar(4),year(@enddate))+'-'+convert(varchar(2),month(@enddate))+'-'+convert(varchar(2),day(@enddate))+' 08:30',@enddate)>0)

begin

set @delayday=@delayday+datediff(mi,convert(varchar(4),year(@enddate))+'-'+convert(varchar(2),month(@enddate))+'-'+convert(varchar(2),day(@enddate))+' 08:30',@enddate)

end

end

end

return @delayday END