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Java递归遍历XML所有元素。

2008-06-12 09:58 441 查看
Java递归遍历XML所有元素
做一个递归遍历XML的例子,为更为复杂的解析工作做基础。

目标:遍历所有的元素节点,并且取出来其中的值,结果打印到控制台。

源代码如下: 本程序依赖DOM4j包

import org.dom4j.Document;

import org.dom4j.DocumentHelper;

import org.dom4j.DocumentException;

import org.dom4j.Element;

import java.util.*;

/**

* Created by IntelliJ IDEA.<br>

* <b>User</b>: leizhimin<br>

* <b>Date</b>: 2008-4-14 14:02:12<br>

* <b>Note</b>: Java递归遍历XML所有元素

*/

public class XmlTest {

//    private static Map<String, String> xmlmap = new HashMap<String, String>();

//存储xml元素信息的容器

private static List<Leaf> elemList = new ArrayList<Leaf>();

//要测试的xml对象

private static String srcXml = "<?xml version=/"1.0/" encoding=/"GBK/"?>/n" +

"<doc>/n" +

"    <person>/n" +

"        <name>某人</name>/n" +

"        <adds>            /n" +

"            <add ID=/"10002/">/n" +

"                <BS>10002</BS>/n" +

"                <note>西安市太白路</note>/n" +

"            </add>/n" +

"            <add ID=/"/">/n" +

"                <BS>10002</BS>/n" +

"                <note>空ID节点啊</note>/n" +

"            </add>/n" +

"            <add>/n" +

"                <BS>10002</BS>/n" +

"                <note>空ID节点啊</note>/n" +

"            </add>/n" +

"/t/t/t<add ID=/"10001/">/n" +

"/t/t/t/t<BS xmlns=/"10001/"/>/n" +

"                <note>西安市太白路2</note>/n" +

"            </add>/n" +

"/t/t</adds>/n" +

"    </person>/n" +

"    <other>/n" +

"        <name ID=/"HEHE/">ASDF</name>/n" +

"    </other>/n" +

"</doc>";

public static void main(String args[]) throws DocumentException {

XmlTest test = new XmlTest();

Element root = test.getRootElement();

test.getElementList(root);

String x = test.getListString(elemList);

system.out.println("-----------原xml内容------------");

system.out.println(srcXml);

system.out.println("-----------解析结果------------");

system.out.println(x);

}

/**

* 获取根元素

*

* @return

* @throws DocumentException

*/

public Element getRootElement() throws DocumentException {

Document srcdoc = DocumentHelper.parseText(srcXml);

Element elem = srcdoc.getRootElement();

return elem;

}

/**

* 递归遍历方法

*

* @param element

*/

public void getElementList(Element element) {

List elements = element.elements();

if (elements.size() == 0) {

//没有子元素

String xpath = element.getPath();

String value = element.getTextTrim();

elemList.add(new Leaf(xpath, value));

} else {

//有子元素

for (Iterator it = elements.iterator(); it.hasNext();) {

Element elem = (Element) it.next();

//递归遍历

getElementList(elem);

}

}

}

public String getListString(List<Leaf> elemList) {

StringBuffer sb = new StringBuffer();

for (Iterator<Leaf> it = elemList.iterator(); it.hasNext();) {

Leaf leaf = it.next();

sb.append(leaf.getXpath()).append(" = ").append(leaf.getValue()).append("/n");

}

return sb.toString();

}

}

/**

* xml节点数据结构

*/

class Leaf {

private String xpath;         //

private String value;

public Leaf(String xpath, String value) {

this.xpath = xpath;

this.value = value;

}

public String getXpath() {

return xpath;

}

public void setXpath(String xpath) {

this.xpath = xpath;

}

public String getValue() {

return value;

}

public void setValue(String value) {

this.value = value;

}

}

运行结果: -----------原xml内容------------

<?xml version="1.0" encoding="GBK"?>

<doc>

<person>

<name>某人</name>

<adds>

<add ID="10002">

<BS>10002</BS>

<note>西安市太白路</note>

</add>

<add ID="">

<BS>10002</BS>

<note>空ID节点啊</note>

</add>

<add>

<BS>10002</BS>

<note>空ID节点啊</note>

</add>

<add ID="10001">

<BS xmlns="10001"/>

<note>西安市太白路2</note>

</add>

</adds>

</person>

<other>

<name ID="HEHE">ASDF</name>

</other>

</doc>

-----------解析结果------------

/doc/person/name = 某人

/doc/person/adds/add/BS = 10002

/doc/person/adds/add/note = 西安市太白路

/doc/person/adds/add/BS = 10002

/doc/person/adds/add/note = 空ID节点啊

/doc/person/adds/add/BS = 10002

/doc/person/adds/add/note = 空ID节点啊

/doc/person/adds/add/*[name()='BS'] =

/doc/person/adds/add/note = 西安市太白路2

/doc/other/name = ASDF

Process finished with exit code 0
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