SQL语句集锦：寻找连续号码的断号值

SELECT /*+ordered */T2.serial_no + 1, MIN (t3.serial_no) - 1

FROM T T1, T T2, T t3

WHERE T1.serial_no(+) = (T2.serial_no + 1) AND T1.serial_no IS NULLAND t3.serial_no > T2.serial_no

GROUP BY T2.serial_no

问题二：

我有一个表结构，
fphm,kshm
2014,00000001
2014,00000002
2014,00000003
2014,00000004
2014,00000005
2014,00000007
2014,00000008
2014,00000009
2013,00000120
2013,00000121
2013,00000122
2013,00000124
2013,00000125

(第二个字段内可能是连续的数据，可能存在断点。)

怎样能查询出来这样的结果,查询出连续的记录来。
就像下面的这样？
2014,00000001,00000005
2014,00000009,00000007
2013,00000120,00000122
2013,00000124,00000125

解决办法：

SQL> spool aaa.log
SQL> set echo on
SQL> select * from t;

no rows selected

SQL> select * from t;

FPHM       KSHM
---------- ----------
2014          1
2014          2
2014          3
2014          4
2014          5
2014          7
2014          8
2014          9
2013        120
2013        121
2013        122

FPHM       KSHM
---------- ----------
2013        124
2013        125

13 rows selected.

SQL> @bbb.sql
SQL> select b.fphm,min(b.kshm),max(b.kshm)
2  from (
3          select a.*,to_number(a.kshm-rownum) cc
4          from (
5                  select * from t order by fphm,kshm
6          ) a
7  )  b
8  group by b.fphm,b.cc
9  /

FPHM MIN(B.KSHM) MAX(B.KSHM)
---------- ----------- -----------
2013         120         122
2013         124         125
2014           1           5
2014           7           9