T-SQL生成两个新的真正的公历年历

--两个新年历
--增加了日期所在月及年的周次!
--星期日要算在"上一周"!(注意WeekOfYear、WeekOfMonth与MyWeekOfYear、MyWeekOfMonth的区别)
--注意datename的值会因语言版本或日期格式有所差异!
--本测试环境为:SQLServer2000简体中文版+Windows简体中文版

declare@datetime
set@='1995-02-2511:00:50'--1995-01-01正好是个星期日

select@as日期
,dateadd(year,datediff(year,0,@),0)as所在年的第一天
,dateadd(year,1+datediff(year,0,@),0)-1as所在年的最后一天
,dateadd(quarter,datediff(quarter,0,@),0)as所在季的第一天
,dateadd(quarter,1+datediff(quarter,0,@),0)-1as所在季的最后一天
,dateadd(month,datediff(month,0,@),0)as所在月的第一天
,dateadd(month,1+datediff(month,0,@),0)-1as所在月的最后一天
,dateadd(week,datediff(week,0,@),0)as所在周的第一天
,dateadd(week,1+datediff(week,0,@),0)-1as所在周的最后一天

selectmonth(min(dateadd(day,0,datediff(day,0,dateadd(day,d.i,dateadd(month,m.i,dateadd(year,datediff(year,0,@),0)))))))as月份
,datepart(week,min(dateadd(day,0,datediff(day,0,dateadd(day,d.i,dateadd(month,m.i,dateadd(year,datediff(year,0,@),0)))))))asWeekOfYear
,datediff(week
,dateadd(month,datediff(month,0,min(dateadd(day,0,datediff(day,0,dateadd(day,d.i,dateadd(month,m.i,dateadd(year,datediff(year,0,@),0))))))),0)
,min(dateadd(day,0,datediff(day,0,dateadd(day,d.i,dateadd(month,m.i,dateadd(year,datediff(year,0,@),0))))))
)+1asWeekOfMonth
,casewhendatename(weekday,min(dateadd(day,0,datediff(day,0,dateadd(day,d.i,dateadd(month,m.i,dateadd(year,datediff(year,0,@),0)))))))='星期日'
thenmin(dateadd(day,0,datediff(day,0,dateadd(day,d.i,dateadd(month,m.i,dateadd(year,datediff(year,0,@),0))))))
elsenullendas星期日
,casewhendatename(weekday,min(dateadd(day,0,datediff(day,0,dateadd(day,d.i,dateadd(month,m.i,dateadd(year,datediff(year,0,@),0)))))))='星期一'
thenmin(dateadd(day,0,datediff(day,0,dateadd(day,d.i,dateadd(month,m.i,dateadd(year,datediff(year,0,@),0))))))
whendatename(weekday,min(dateadd(day,0,datediff(day,0,dateadd(day,d.i,dateadd(month,m.i,dateadd(year,datediff(year,0,@),0))))))+1)='星期一'
anddatediff(month,min(dateadd(day,0,datediff(day,0,dateadd(day,d.i,dateadd(month,m.i,dateadd(year,datediff(year,0,@),0)))))),min(dateadd(day,0,datediff(day,0,dateadd(day,d.i,dateadd(month,m.i,dateadd(year,datediff(year,0,@),0))))))+1)=01