input and output
2007-04-13 15:17
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要使用基本的输入输出,我们得在源代码开头加上 Imports System 导入System命名空间。
控制台下的输入输出由System.Console类来管理。基本的输入是Console.ReadLine/Console.Read,输出是Console.WriteLine/Console.Write。
[example]
public Module MainModule
public Sub Main()
dim str as String
str = Console.ReadLine '读入用户输入的一行
Console.WriteLine(str) '将读入的内容输出
Console.ReadLine
end sub
end Module
[example]
public Sub Main()
dim str as String
Console.WriteLine("What is your name?")
str = Console.ReadLine
Console.WriteLine("Hello, " & str & "!")
Console.Read
end sub
[example]
public Sub Main()
dim i, j as integer
Console.WriteLine("第一个数:")
'Console.ReadLine接受的是字符串,我们用cint函数将字符串转换成整数
i = cint(Console.ReadLine)
Console.WriteLine("第二个数:")
j = cint(Console.ReadLine)
Console.WriteLine("结果是:" & i + j)
Console.Read
end sub
[example]
public Sub Main()(Byval Args() as String)
dim str as String()
dim i as integer
Console.WriteLine("Length of Args is " & Args.Length)
for i = 0 to Args.Length - 1
Console.WriteLine("Args(" & i & "):" & Args(i))
next
Console.Read
end sub
[example]
public Sub Main()sub Main()
dim i, j as integer
Console.WriteLine("第一个数:")
i = cint(Console.ReadLine)
Console.WriteLine("第二个数:")
j = cint(Console.ReadLine)
'这里使用了格式化的方式来输出结果。花括号括起来的数字表示第几个参数,
'后面按顺序列出值。这就相当于C中的printf("%s:%i", "结果是", i+j);
Console.WriteLine("{0}:{1}", "结果是", i + j)
Console.Read
end sub
控制台下的输入输出由System.Console类来管理。基本的输入是Console.ReadLine/Console.Read,输出是Console.WriteLine/Console.Write。
[example]
public Module MainModule
public Sub Main()
dim str as String
str = Console.ReadLine '读入用户输入的一行
Console.WriteLine(str) '将读入的内容输出
Console.ReadLine
end sub
end Module
[example]
public Sub Main()
dim str as String
Console.WriteLine("What is your name?")
str = Console.ReadLine
Console.WriteLine("Hello, " & str & "!")
Console.Read
end sub
[example]
public Sub Main()
dim i, j as integer
Console.WriteLine("第一个数:")
'Console.ReadLine接受的是字符串,我们用cint函数将字符串转换成整数
i = cint(Console.ReadLine)
Console.WriteLine("第二个数:")
j = cint(Console.ReadLine)
Console.WriteLine("结果是:" & i + j)
Console.Read
end sub
[example]
public Sub Main()(Byval Args() as String)
dim str as String()
dim i as integer
Console.WriteLine("Length of Args is " & Args.Length)
for i = 0 to Args.Length - 1
Console.WriteLine("Args(" & i & "):" & Args(i))
next
Console.Read
end sub
[example]
public Sub Main()sub Main()
dim i, j as integer
Console.WriteLine("第一个数:")
i = cint(Console.ReadLine)
Console.WriteLine("第二个数:")
j = cint(Console.ReadLine)
'这里使用了格式化的方式来输出结果。花括号括起来的数字表示第几个参数,
'后面按顺序列出值。这就相当于C中的printf("%s:%i", "结果是", i+j);
Console.WriteLine("{0}:{1}", "结果是", i + j)
Console.Read
end sub
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