习题5.7参考答案（傻瓜版）

/*
Name: xt5_7.c
Copyright: 允许任意copy
Author: 姚果
Date: 22-11-05 20:56
Description: 课本p105页习题5.7参考答案
没有用循环，用的比较傻瓜的方法作，但是很好理解，
更加经典的写法大家先多多考虑一下，学了循环之后我再贴出来
*/
main()
{
long int num;
int indiv,ten,hundred,thousand,ten_thousand,place;
/*分别代表个位、十位、百位、千位、万位和位数*/
printf("请输入一个整数（0~99999）：");
scanf("%ld",&num);
if (num>9999) place=5;
else if(num>999) place=4;
else if(num>99) place=3;
else if(num>9) place=2;
else place=1;
printf("place =%d/n", place);
ten_thousand=num/10000;
thousand=num/1000%10;
hundred=num/100%10;
ten=num%100/10;
indiv=num%10;
switch(place)
{ case 5: printf("%d,%d,%d,%d,%d",ten_thousand,thousand,hundred,ten,indiv);
printf("/n反序数字为；");
printf("%d%d%d%d%d/n",indiv,ten,hundred,thousand,ten_thousand);
break;
case 4: printf("%d,%d,%d,%d",thousand,hundred,ten,indiv);
printf("/n反序数字为：");
printf("%d%d%d%d/n",indiv,ten,hundred,thousand);
break;
case 3: printf("%d,%d,%d",hundred,ten,indiv);
printf("/n反序数字为：");
printf("%d%d%d/n",indiv,ten,hundred);
break;
case 2: printf("%d,%d",ten,indiv);
printf("/n反序数字为：");
printf("%d%d/n",indiv,ten);
break;
case 1: printf("%d",indiv);
printf("/n反序数字为：");
printf("%d/n",indiv);
break;
}
getch();
}